Append keys to existing array value

Question

I have the following array and by using array_push & I am getting not the right result.

Array:

Array
(
    [0] => 1039
    [1] => 417
    [2] => 418
)

Array Push:

array_push($array, array("a","b","c"));

Result:

Array
(
    [0] => 1039
    [1] => 417
    [2] => 418
    [3] => Array
    (
        [0] => a
        [1] => b
        [2] => c
    )

)

I want the a,b,c append to value 417 for example .

Disirable result:

Array
(
    [1039] => 1039
    [417] => Array
    (
        [0] => a
        [1] => b
        [2] => c
    )
    [418] => 418

)

How can this be done?

SOLUTION:

$data = Array (
    0 => 1039,
    1 => 417,
    2 => 418,
 );

foreach( $data as $key => $val ) {
    $new_data[$val] = 0;
}

foreach( $new_data as $k => $v ){
    if( $k == 417 ){
        $new_data[$k] = array( 'p' => 50, 'pp' => 75 );
    }
}
print_r($new_data);

Your desired result isn't a valid PHP object. You can't have both a number and an array in the same array element. — Barmar
– Barmar, Commented Dec 17, 2013 at 4:27
Hi Barmar. I want to append to for example an array to value 417 — Bas
– Bas, Commented Dec 17, 2013 at 4:32
You want to replace the value of $array[1] with an array? What do you mean by append? — Ja͢ck
– Ja͢ck, Commented Dec 17, 2013 at 4:33
I have 1 array and i want to add the other one to value 417. Is that possible? — Bas
– Bas, Commented Dec 17, 2013 at 4:35

Barmar · Accepted Answer · 2013-12-17 04:53:41Z

1

It doesn't really make sense, but this will do what you show in your example:

$array[1] .= print_r(array("a","b","c"), true);

.= does string concatenation, and passing true as the second argument to print_r makes it return the string that it would have printed.

The result of this is that $array[1] is a string that begins with 417 and is followed by the printed representation of the added array. There's no actual array in there. I'm not sure what you plan to do with this, but it matches your example.

edited Dec 17, 2013 at 4:53

answered Dec 17, 2013 at 4:38

Barmar

789k57 gold badges554 silver badges669 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

zai · Accepted Answer · 2013-12-17 05:32:11Z

0

use loop to display new array data

 $data = Array (
      0 => 1039,
      1 => 417,
      2 => 418,
      );

 foreach( $data as $key => $val ) {
     if ( $val == 417 ) {
         $val = array( 'a','b','c' );
     }

     $new_data = array( $key => $val );
     foreach( $new_data as $key2 => $val2 ) {
         if ( is_array( $val2 ) ) {
             $val2 = array( 417 => $val );
         }
         $new_data1 = array( $key2 => $val2 );

    print_r($new_data1);
    }
}

edited Dec 17, 2013 at 5:32

answered Dec 17, 2013 at 4:39

zai

7510 bronze badges

1 Comment

Bas Over a year ago

Almost! Where is my number 417? I need that as well.

Zarathuztra · Accepted Answer · 2013-12-17 04:26:16Z

0

Don't use array push in this case (granted I might be missing your question)

$arr = array(1,2,3);
$arr[1] = array('a','b','c');
//would output your above example.

answered Dec 17, 2013 at 4:26

Zarathuztra

3,2411 gold badge22 silver badges34 bronze badges

2 Comments

Barmar Over a year ago

This replaces 417 with the new sub-array, it doesn't append it like in his desired result (which, granted, isn't actually possible).

Zarathuztra Over a year ago

Yeah, I agree his original isn't possible, so I was hoping and praying it was just a typo ;)

Giacomo1968 · Accepted Answer · 2013-12-17 04:26:33Z

0

Just do it like this & all should work as expected:

array_push($array, "a", "b", "c");

The array_push manual page explains it best:

$stack = array("orange", "banana");
array_push($stack, "apple", "raspberry");
print_r($stack);

But if the values you are adding are in an array already, then perhaps use array_merge instead:

array_merge($array, array("a","b","c"));

answered Dec 17, 2013 at 4:26

Giacomo1968

25.4k11 gold badges78 silver badges106 bronze badges

1 Comment

Barmar Over a year ago

This won't produce his desired result.

Vitalii · Accepted Answer · 2013-12-17 04:29:27Z

0

My running php code:

$arr = array(0=>1039,1=>417,2=>418);
array_push($arr, array("a","b","c"));
var_dump($arr);

And var_dump($arr)

array(4) { [0]=> int(1039) [1]=> int(417) [2]=> int(418) [3]=> array(3) { [0]=> string(1) "a" [1]=> string(1) "b" [2]=> string(1) "c" } }

answered Dec 17, 2013 at 4:29

Vitalii

1551 silver badge10 bronze badges

2 Comments

Barmar Over a year ago

How is this different from what he does in his question?

Vitalii Over a year ago

Maybe You forgot something. Please type your code (not print_r($array)) or var_dump($array).

Linga · Accepted Answer · 2013-12-17 04:33:32Z

0

Use array_splice

array_splice($your_arrray, 1, 0, array("a","b","c"));

answered Dec 17, 2013 at 4:33

Linga

10.6k10 gold badges57 silver badges109 bronze badges

Collectives™ on Stack Overflow

Append keys to existing array value

6 Answers 6

Comments

1 Comment

2 Comments

1 Comment

2 Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

6 Answers 6

Comments

1 Comment

2 Comments

1 Comment

2 Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related