I'm trying to be able call a function that is nested.
def function1():
#code here
def function2():
return #variable
def function3():
x = #the variable that is returned in function2
# I'm not sure how to get it to equal the variable that was returned in function2
Thanks for the help!
You would have to return the function object; function2 is just another local variable inside function1 otherwise:
def function1():
#code here
def function2():
return foo
return function2
def function3():
x = function1()() # calls function2, returned by function1()
Calling function1() returns the function2 object, which is then called immediately.
Demo:
>>> def foo(bar):
... def spam():
... return bar + 42
... return spam
...
>>> foo(0)
<function spam at 0x10f371c08>
>>> foo(0)()
42
>>> def ham(eggs):
... result = foo(eggs + 3)()
... return result
...
>>> ham(38)
83
Note how calling foo() returns a function object.
To make that happen, you have to return function2 from function1 and then call function2 from function3 like this
def function1():
#code here
def function2():
return #variable
return function2
def function3():
x = function1()
print x()
Or, instead of storing function2 in x, you can simply do
def function3():
print function1()()
