PHP Create an Array or String based on condition

Question

In the following code, I'm trying to create an array or a string based on if type is true or false. If type were true, then i need to create an array else I need to keep things as a string. I was trying as below, but it does not seem to work. Can you help?

<?php
$type = True;

if($type){
    $body = "body['body']"; //Start an array
} else {
    $body = 'body'; //Just a string
}

$body  = 'Hello'; //$body = the value from up there

print_r($body);
?>

Expected Results:

If type = true //Array
print_r($body);
Array ([body] => Hello)

If type = false //String
print_r($body); 
Hello

Edit The content for the array or string is outside the if and comes after it. I need to start as a array or sting based on the type.

Whatever executes inside the if - else statement is pretty useless here .. because you are just overwriting it with $body = 'Hello' after the end of the if-else — Shankar Narayana Damodaran
– Shankar Narayana Damodaran, Commented Jan 6, 2014 at 6:32

웃웃웃웃웃 · Accepted Answer · 2014-01-06 06:31:41Z

3

$type  = true;
$value = 'Hello';

if($type){
    $body['body'] = $value;
} else {
    $body = $value;
}

print_r($body);

answered Jan 6, 2014 at 6:31

웃웃웃웃웃

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3 Comments

Norman Over a year ago

The content for the array or string is outside the if.

Norman Over a year ago

I forgot to add, the content is set after the if. Which is why I posted that way.

Mathew Over a year ago

$value needs to be assigned inside the if to ensure the type of $body is as expected.

Rohan · Accepted Answer · 2014-01-06 06:32:30Z

0

Try this.

$x = array('body'=>'Hello');
if($type){
    $body = $x;
} else {
    $body = 'body';
}

answered Jan 6, 2014 at 6:32

Rohan

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2 Comments

Norman Over a year ago

The content for the array or string is outside the if

Rohan Over a year ago

check it now - this should be fine.

loler · Accepted Answer · 2014-01-06 06:34:19Z

0

You can write it on one line with shorthand if.

$body = ($type ? array('body'=>'Hello') : 'Hello');

var_dump($body);

answered Jan 6, 2014 at 6:34

loler

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Comments

Junaid Atique · Accepted Answer · 2014-01-06 06:49:24Z

0

$type  = true;
$value = 'Hello';

if($type){
    $body['body'] = $value;
} else {
    $body = $value;
}
if (is_array($body)) {
// content for array goes here
} else {
// content for string goes here
}
print_r($body);

answered Jan 6, 2014 at 6:49

Junaid Atique

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