PHP - Create multiple arrays based on value

Question

I have an array like this:

$r = array();
$r[] = ['name' => 'Test', 'supplierId' => 34];
$r[] = ['name' => 'Test2', 'supplierId' => 31];
$r[] = ['name' => 'Test3', 'supplierId' => 32];
$r[] = ['name' => 'Test4', 'supplierId' => 34];
$r[] = ['name' => 'Test5', 'supplierId' => 30];
$r[] = ['name' => 'Test6', 'supplierId' => 32];

Now I want to take $r and get multiple arrays back, differenced by supplierId. So I am looking for this result:

    $r30 = ['name' => 'Test5', 'supplierId' => 30];
    $r32 = [
    ['name' => 'Test3', 'supplierId' => 32],
    ['name' => 'Test6', 'supplierId' => 32]
    ];

I tried it with, but here I do not have access to $sup in array_filter.

$supplier = array(30, 31, 32, 34);
$finalArray = [];

foreach ($supplier as $sup) {
    $finalArray[] = array_filter($r, function($value, $sup) {
        echo $sup;
        if ($value['supplierId'] == $sup) {
            return true;
        }
    });
}//foreach

Any idea how I can solve it? Is there no native function that accomplishes this - something like create_array_based_on('supplierId');?

Thanks

Would $r30 = [['name' => 'Test5', 'supplierId' => 30]]; be suitable? — Alex Blex
– Alex Blex, Commented Mar 21, 2017 at 14:12

jeroen · Accepted Answer · 2017-03-21 14:18:02Z

2

You can pass $sup to your anonymous function:

foreach ($supplier as $sup) {
    $finalArray[] = array_filter($r, function($value) use ($sup) {
                                                      ^^^^^^^^^^ you need to pass
                                                                 it like this
        echo $sup;
        if ($value['supplierId'] == $sup) {
            return true;
        }
    });
}//foreach

But personally I would probably just loop over the original array and use the supplier ID as a key.

Something like:

$results = [];
foreach ($r as $value) {
    $results[$value['supplierId']][] = $value;
}

answered Mar 21, 2017 at 14:18

jeroen

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Comments

KarlsMaranjs · Accepted Answer · 2017-03-21 14:27:00Z

1

Try this out

$r = array();
$r[] = ['name' => 'Test', 'supplierId' => 34];
$r[] = ['name' => 'Test2', 'supplierId' => 31];
$r[] = ['name' => 'Test3', 'supplierId' => 32];
$r[] = ['name' => 'Test4', 'supplierId' => 34];
$r[] = ['name' => 'Test5', 'supplierId' => 30];
$r[] = ['name' => 'Test6', 'supplierId' => 32];

$supplier = array(30, 31, 32, 34);
$finalArray = [];


$i=0;
foreach ($supplier as $sup) {
    $value =$r[$i]['supplierId'];
    if($value==$sup)
    {
        $finalArray[] = $value;
    }

 $i++;

}//foreach

$finalArray is a new array with all values you need

answered Mar 21, 2017 at 14:27

KarlsMaranjs

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Comments

Alex Blex · Accepted Answer · 2017-03-21 14:18:34Z

0

You can combine array_filter and in_array as following:

$finalArray[] = array_filter($r, function($value) use ($supplier) {
    return in_array($value['supplierId'], $supplier);
});

Without foreach loop.

answered Mar 21, 2017 at 14:18

Alex Blex

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Comments

CMR · Accepted Answer · 2017-03-21 14:20:14Z

It would be much easier, instead of wanting new variables for each of them, like $r32, $r35, etc... if you just used the array keys to store the supplierid, e.g.

$r = array();
$r[] = ['name' => 'Test', 'supplierId' => 34];
$r[] = ['name' => 'Test2', 'supplierId' => 31];
$r[] = ['name' => 'Test3', 'supplierId' => 32];
$r[] = ['name' => 'Test4', 'supplierId' => 34];
$r[] = ['name' => 'Test5', 'supplierId' => 30];
$r[] = ['name' => 'Test6', 'supplierId' => 32];

$newArray = array();

foreach($r as $key => $element)
{
    if (!isset($newArray[$element['supplierId']])){
        $newArray[$element['supplierId']] = array();
    }
    $newArray[$element['supplierId']][] = $element;
}

That would give you an output of:

<pre>Array
(
    [34] => Array
        (
            [0] => Array
                (
                    [name] => Test
                    [supplierId] => 34
                )

            [1] => Array
                (
                    [name] => Test4
                    [supplierId] => 34
                )

        )

    [31] => Array
        (
            [0] => Array
                (
                    [name] => Test2
                    [supplierId] => 31
                )

        )

    [32] => Array
        (
            [0] => Array
                (
                    [name] => Test3
                    [supplierId] => 32
                )

            [1] => Array
                (
                    [name] => Test6
                    [supplierId] => 32
                )

        )

    [30] => Array
        (
            [0] => Array
                (
                    [name] => Test5
                    [supplierId] => 30
                )

        )

)
</pre>

RomanPerekhrest · Accepted Answer · 2017-03-21 14:21:03Z

0

It's about simple grouping nested arrays by some key value:

$finalArr = [];
foreach ($r as $arr) {
    $finalArr[$arr['supplierId']][] = $arr;
}

print_r($finalArr);

DEMO link

answered Mar 21, 2017 at 14:21

RomanPerekhrest

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