Pass bash variables into subprocess arguments

Question

In a bash shell script I would like to do the following:

for file in /path/to/original/*
  nfcapd -p 12345 -l /path/to/new/file/ -x 'mv %d%f %d/$file'
done

So nfcapd -x lets you add a command to execute on completion. I want to mv %d%f (move directorypath/defaultfilename) to %d/$file (directorypath/original_file_name). Unfortunately, this is saving the new file as "$file" not the value of the $file variable. Is there a way to escape the quotes?

Jakub Kotowski · Accepted Answer · 2014-01-14 18:17:23Z

1

Use double quotes instead of single quotes around the argument to -x, it will be:

nfcapd -p 12345 -l /path/to/new/file/ -x "mv %d%f %d/$file"

Shell variables are not expanded inside single quotes.

edited Jan 14, 2014 at 18:17

answered Jan 14, 2014 at 18:03

Jakub Kotowski

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