How to pass parameters from bash to php script?

Question

I have done a a bash script which run php script. It works fine without parameters but when I add parameters (id and url), there are some errors:

PHP Deprecated:  Comments starting with '#' are deprecated in /etc/php5/cli/conf                                                                                        .d/mcrypt.ini on line 1 in Unknown on line 0
Could not open input file: /var/www/dev/dbinsert/script/automatisation.php?                                                                                        id=1

I run php script from the bash like this:

php /var/www/dev/dbinsert/script/automatisation.php?id=19&url=http://bkjbezjnkelnkz.com

Zuul · Accepted Answer · 2012-10-04 18:07:53Z

34

Call it as:

php /path/to/script/script.php -- 'id=19&url=http://bkjbezjnkelnkz.com'

Also, modify your PHP script to use parse_str():

parse_str($argv[1]);

If the index $_SERVER['REMOTE_ADDR'] isn't set.

More advanced handling may need getopt(), but parse_str() is a quick'n'dirty way to get it working.

edited Oct 4, 2012 at 18:07

Zuul

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answered Jul 21, 2011 at 16:47

Tino Didriksen

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3 Comments

Michael Over a year ago

How would you pass a directory into the php script?

Tino Didriksen Over a year ago

@Michael, same way, just read it from the $argv array. Also, thread necromancy is bad.

ZomoXYZ Over a year ago

I'm not sure if I did something wrong, or if the php has changed, but it is unnecessary to use the --. When I use $argv[1], it just reads the --.

Patrick Cavanaugh · Accepted Answer · 2011-07-21 16:54:21Z

6

You can't pass GET query parameters to the PHP command line interface. Either pass the arguments as standard command line arguments and use the $argc and $argv globals to read them, or (if you must use GET/POST parameters) call the script through curl/wget and pass the parameters that way – assuming you have the script accessible through a local web server.

This is how you can pass arguments to be read by $argc and $argv (the -- indicates that all subsequent arguments should go to the script and not to the PHP interpreter binary):

php myfile.php -- argument1 argument2

answered Jul 21, 2011 at 16:54

Patrick Cavanaugh

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1 Comment

Bastion Over a year ago

You can pass GET query parameters if you use php-cgi :) See examples here: serverfault.com/questions/187025/…

Bastion · Accepted Answer · 2017-08-06 23:29:08Z

6

-- Option 1: php-cgi --

Use 'php-cgi' in place of 'php' to run your script. This is the simplest way as you won't need to specially modify your php code to work with it:

php-cgi -f /my/script/file.php id=19 myvar=xyz

-- Option 2: if you have a web server --

If the php file is on a web server you can use 'wget' on the command line:

wget 'http://localhost/my/script/file.php?id=19&myvar=xyz'

OR:

wget -q -O - "http://localhost/my/script/file.php?id=19&myvar=xyz"

-- Accessing the variables in php --

In both option 1 & 2 you access these parameters like this:

$id = $_GET["id"];
$myvar = $_GET["myvar"];

edited Aug 6, 2017 at 23:29

answered Apr 22, 2015 at 2:11

Bastion

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