php if echo something else echo else for html

Question

So here's my code, I try to make for my pagination function to echo something if is on homepage and echo else if is on another page like page=2 or page3 ++

<?php if(empty($_GET) or ($_GET['pg']==1)) { echo ' ?> Html codes content and php <?php '; } else { echo '?> Else html codes content and php <?php '; } ?>

But is not working, i'm sure is from the " ' " or " '' " something i put wrong but where? where or what is the problem

Barmar · Accepted Answer · 2014-03-15 11:54:14Z

2

Don't put ?> in the echo statement.

<?php 
if(empty($_GET) || $_GET['pg'] ==1) {
    echo 'HTML codes content';
} else {
    echo 'Else html codes content';
}
?>

You can also do it by closing the PHP and not using echo:

<?php
if (empty($_GET) || $_GET['pg'] ==1) { ?>
    HTML codes content
<?php else { ?>
    Else html codes content
<?php } ?>

edited Mar 15, 2014 at 11:54

answered Mar 15, 2014 at 11:47

Barmar

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2 Comments

John Smith Over a year ago

it works thanks so to close the php after echo is not acceptable.

Barmar Over a year ago

Right. You either use echo or you close the PHP, you don't do both.

Félix Sanz · Accepted Answer · 2014-03-15 12:00:51Z

You can use a ternary operator to make it simpler. Also it's better to use isset() because even if $_GET is not empty, that doesn't mean that $_GET['pg'] exists, so it will generate warnings.

Anyway as pointed out above, the problem is that you are using ?> inside the echo statement, which is incorrect.

You can do for example:

<?php if ((isset($_GET['pg'])) && ($_GET['pg']==1)) { ?>Html codes content and php<?php } else { ?>Else html codes content and php<?php } ?>

Using a ternary operator:

<?php echo ((isset($_GET['pg'])) && ($_GET['pg']==1)) ? 'Html codes content and php' : 'Else html codes content and php'; ?>

Using a ternary operator and short tags:

<?=((isset($_GET['pg'])) && ($_GET['pg']==1)) ? 'Html codes content and php' : 'Else html codes content and php'; ?>

Renaud is Not Bill Gates · Accepted Answer · 2014-03-15 11:53:55Z

0

You cannot have PHP code in echo, because PHP will interpret your code in a single pass.

Your code should be like this :

<?php 
    echo (empty($_GET) || ($_GET['pg']==1)) ? 
         'Html code':
         'Another HTML code';
?>

If you need to output some PHP code, there is always a better way to accomplish it, you can include some file that contains the php code you want to add.

answered Mar 15, 2014 at 11:53

Renaud is Not Bill Gates

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Comments

Md. Al-Amin · Accepted Answer · 2014-03-15 11:59:58Z

0

You can use this way.

<?php if(empty($_GET) || $_GET['pg'] ==1): ?>
    <p>HTML codes content</p> 
<?php else: ?>
    <p>Else html codes content<p>
<?php endif; ?>

Note that : I used direct html code.

answered Mar 15, 2014 at 11:59

Md. Al-Amin

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