Jquery + $.each + dynamic operation + using parameters

Question

function Controles(contro, nomtab, numtab, action, nomcla, tipdat, lista, datos) {

    $(document).on('click', '.'+contro+' #IZQTOD', function(event) {
        $.getJSON(action+'&rows='+rows+'&page=1', function(datos) {
            var nuevafila;
            $.each(datos+tipdat, function(index, data) {
                nuevafila = nuevafila + "<tr class='Fila-Grid-"+nomcla+"' id='" + numtab + (index + 1) + "'>";
                nuevafila = nuevafila + "<td class='Columna1'>" + (index + 1) + "</td>";
                var list = lista.split("-");
                for (var j = 1; j < list.length; j++) {
                    nuevafila = nuevafila + "<td class='Borde-'>" + data+list[j] + "</td>"; 
                }
                nuevafila = nuevafila + "</tr>";
            });
            $('#'+nomtab+' tr:eq(1)').after(nuevafila);
        });
    });
}

I want to run this piece of code as a function of javascript in order to reuse code. The part that does not work for me is the part of each: $. each (+ tipdat data, function (index, data) {

Where "datos" is an object with variables (set and get) (codcli, name, apepat) I mean to call codcli I do:

   $. each (datos.codcli, function (index, data) {
}

But this way is static. I want to do through dynamic parameters.

So the question is how to pass parameters to successfully achieve? Or is that you can not do? There will always be static?

in the code above what I want to do is, but obviously does not work:

tipdat=".codcli"
   $. each (datos+tipdat, function (index, data) {
}

For this example, could you translate to english? This makes no sence if you don't understand the language :) — Martijn
– Martijn, Commented Mar 25, 2014 at 17:29
please clean up the last to code examples, they are not easy to follow. thanks. :) — winner_joiner
– winner_joiner, Commented Mar 25, 2014 at 17:36
Please consider reading about dynamic-programming , it's not what you're doing here at all. — Benjamin Gruenbaum
– Benjamin Gruenbaum, Commented Mar 25, 2014 at 17:37

Jason P · Accepted Answer · 2014-03-27 19:12:04Z

1

I think you're looking for bracket notation.

var tipdat = "codcli";
$.each(datos[tipdat], function (index, data) {
    //...
});

Is the same as:

$.each(datos.codcli, ...

If your string has multiple properties, I would do something like this:

var tipdat = "codcli.cod";

var objToIterate = datos;
var parts = tipdate.split('.');

for(var i = 0; i< parts.length; i++) {
    objToIterate = objToIterate[parts[i]];   
}

$.each(objToIterate, function (index, data) {
    //...
});

edited Mar 27, 2014 at 19:12

answered Mar 25, 2014 at 17:47

Jason P

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5 Comments

Ivan Over a year ago

I think this is what I seek. Tomorrow at work I try and give you your point.

Ivan Over a year ago

that works good. last question: Whats up if var tipdat = "codcli" is tipdat = "codcli.cod" ?

Ivan Over a year ago

I was referring to: $.each(datos.codcli.cod, ... is the same to: $.each(datos[parts[0]][parts[1]], ... ?

Jason P Over a year ago

What I posted should give you same result as $.each(datos.codcli.cod, ...

Ivan Over a year ago

i have problems with the sintaxis: i opened other question. help me there plz. stackoverflow.com/questions/22720296/…

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