Calling a Javascript function from PHP with variables created in php

Question

I have a javascript function in a file comment_insert.js:

  function comment_insert(data,ul_id) {

        var t = '';
        t += '<li class="comment-holder" id="_' + data.comment_id + '">';
        t += '<div class="user-img">';
        t += '<img src="' + data.profile_img + '" class="user-img-pic" />';
        t += '</div>';
        t += '<div class="comment-body">';
        t += '<h3 class="username-field" >' + data.Username + '</h3>';
        t += '<div class="comment-text">' + data.comment + '</div>';
        t += '</div>';
        t += '<div class="comment-buttons-holder">';
        t += '<ul>';
        t += '<li class="delete-btn">[x]</li>';
        t += '</ul>';
        t += '</div>';
        t += '</li>';

        $('#' + ul_id).prepend(t);
    }

I want to call this function from a php file display.php as:

$smthng = new stdClass();
        $smthng->comment_id = 24;
        $smthng->Userid = 1;
        $smthng->comment = "Hard coded comments";
        $smthng->Username = "Sagar_username"; 
        //$smthng->profile_img = "images/Setting-icon.png";


        $data =  json_encode($smthng);
                $ul_id = "ul218";

 comment_insert(jQuery.parseJSON($data),$ul_id);

The function being called is the same as in comment_insert.js which accepts 2 inputs (data and ul_id). These are being created in display.php and then I want to execute the function.

PHP runs on the server, Javascript runs on the client. You can NOT call one from the other. At best you can do an AJAX call from client->server to invoke php code and get its output. — Marc B
– Marc B, Commented Apr 4, 2014 at 14:21
Could you provide me the ajax call that would solve this problem ? — Hardik Dave
– Hardik Dave, Commented Apr 4, 2014 at 14:22
I am so tired of the questions starting with the phrase Calling a Javascript function from PHP — Molecular Man
– Molecular Man, Commented Apr 4, 2014 at 14:23

Tom G · Accepted Answer · 2014-04-04 14:23:18Z

1

Assuming that the PHP code is in the same file as Javascript and is being used for front end out put to the browser, you can do this:

<?php
$smthng = new stdClass();
        $smthng->comment_id = 24;
        $smthng->Userid = 1;
        $smthng->comment = "Hard coded comments";
        $smthng->Username = "Sagar_username"; 
        //$smthng->profile_img = "images/Setting-icon.png";


        $data =  json_encode($smthng);
                $ul_id = "ul218";
?>
<script type="text/javascript">
    comment_insert(jQuery.parseJSON(<?php echo $data ?>), <?php echo $ul_id ?>);
</script>

However, if this is not in a file that is producing output to the browser, you cannot execute Javascript server-side

answered Apr 4, 2014 at 14:23

Tom G

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3 Comments

Hardik Dave Over a year ago

Variable creation and function call are to be executed in the same for{} loop which is in php code. Hence, I could not end my php code and start a <script> tag to call the function.

Tom G Over a year ago

Then I refer you to the comments on your original question, Javascript cannot be executed server-side unless you do something akin to what madhippie is suggesting (using the V8js extension)

Brian Glaz Over a year ago

You can add script blocks between php blocks, even in a for loop. just end the php ?> write the script block, and open the again <?php

Community · Accepted Answer · 2023-11-17 19:32:19Z

In order to execute Javascript in PHP you'll need to install the V8js Extension.

After installing you should parse your comment_insert.js to a PHP variable via file_get_contents and execute it somehow like this:

<?php

$v8 = new V8Js();

/* Get you js file's content */
$JS = file_get_contents("PATH/TO/JS-FILE/comment_insert.js");

try {
  $v8->executeString($JS, 'basic.js');
} catch (V8JsException $e) {
  var_dump($e);
}

?>

Note: In order to make it work, I think you'll replace the jQuery call with native JS.

So modify you comment_insert.js to something like this:

  function comment_insert(data,ul_id) {

    var t = '';
    t += '<li class="comment-holder" id="_' + data.comment_id + '">';
    t += '<div class="user-img">';
    t += '<img src="' + data.profile_img + '" class="user-img-pic" />';
    t += '</div>';
    t += '<div class="comment-body">';
    t += '<h3 class="username-field" >' + data.Username + '</h3>';
    t += '<div class="comment-text">' + data.comment + '</div>';
    t += '</div>';
    t += '<div class="comment-buttons-holder">';
    t += '<ul>';
    t += '<li class="delete-btn">[x]</li>';
    t += '</ul>';
    t += '</div>';
    t += '</li>';
  
    //$('#' + ul_id).prepend(t);
    elem = document.getElementById(ul_id);
    elem.insertBefore(t);  
}

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