Is this possible in Python? I wrote a great loop/script in Python and I’d like to add this delay to it if at all possible.
map(firefox.open, ['http://www.bing.com/search?q=' + str(i) for i in range(x))], [2] * x)
Where shall I put the sleep(6) in this?
You can do that using time.sleep(some_seconds).
from time import sleep
for i in range(10):
print i
sleep(0.5) #in seconds
Here is a cool little implementation of that: (Paste it in a .py file and run it)
from time import sleep
for i in range(101):
print '\r'+str(i)+'% completed',
time.sleep(0.1)
map(firefox.open, ['http://www.bing.com/search?q=' + str(i) for i in range(x))], [2] * x)
map(firefox.open, ['http://www.bing.com/search?q=' + str(i) for i in range(x))], [2] * x) Where shall I put the sleep(6) in this?
firefox.open and stuff so I am currently not understanding.Or if you want it to start on one and emulate a stopwatch:
import time
def count_to(number):
for i in range(number):
time.sleep(1)
i += 1
if i >= number:
print('Time is up')
break
print(i)
Yes it is possible in python you should use 'time' module:
>>> import time
>>> list1=[1,2,3,4,5,6,7,8,9,10]
>>> for i in list1:
time.sleep(1)#sleep for 1 second
print i
output :
1
2
3
4
5
6
7
8
9
10
