Python Delay on Loop

Question

I need an alternative to "delay" actions on a LOOP. When using time.sleep(1) the whole process pauses for a second. The print 'something' should be executed after every 1 second, 50 times and not interrupting the rest of the process.

Actual code:

for num in range(50, -1, -1):
    print 'something'
    time.sleep(1)

Amadan · Accepted Answer · 2015-08-18 06:37:19Z

1

If I understand what you want, you need to use threads. One thread will do exactly what you did: just count and sleep. The other thread will be "the rest of process", doing whatever it wants, without being interrupted by sleeping.

import time
import threading

def count():
    for num in range(50, -1, -1):
        print 'something'
        time.sleep(1)

count_thread = threading.Thread(target=count)
count_thread.start()

for num in range(10, -1, -1):
    print 'main'
    time.sleep(5)

count_thread.join()

edited Aug 18, 2015 at 6:37

answered Aug 18, 2015 at 6:32

Amadan

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2 Comments

user3211337 Over a year ago

Any idea with code? I tried threads.Timer, but it keep repeating the action.

user3211337 Over a year ago

Did not solve the problem, if a use a function from a class, the hole class pauses(their process and all). E.g: def count(): for num in range(50, -1, -1): Class().someFunction(num) time.sleep(1)

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