changing time format with preg replace in php

Question

i m just wondering if we can do this with preg replace

like if there's time like

1h 38 min

can change to

98 mins

2h 20 min

can change to

140 mins

or just suggest me any other random function to this is simpler way

thanks

sometimes it comes like 1h 38 min and sometimes its like 2h 20 min, thing is like 1 hours or 2 hours — Jegeg
– Jegeg, Commented Feb 24, 2010 at 2:23

gnud · Accepted Answer · 2010-02-24 02:06:11Z

2

This simple function should do the trick. It does no verification on the string format, though.

function reformat_time_string($timestr) {
    $vals = sscanf($timestr, "%dh %dm");
    $total_min = ($vals[0] * 60) + $vals[1];
    return "$total_min mins";
}

$timestr = "2h 15m";
echo reformat_time_string($timestr); /* echoes '135 mins' */

answered Feb 24, 2010 at 2:06

gnud

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ghostdog74 · Accepted Answer · 2010-02-24 02:10:29Z

0

$str="1h 38 min";
$s = explode(" ",$str);
if ( strpos ( $s[0] ,"h" ) !==FALSE) {
    $hr=str_replace("h","",$s[0]);
    print ($hr*60) + $s[1]."\n";
}

answered Feb 24, 2010 at 2:10

ghostdog74

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VolkerK · Accepted Answer · 2010-02-24 02:07:29Z

0

$pattern = '!(\d+)\s*h\s*(\d+)\s*min!';
foreach( array('1h 38 min', '2h 20 min') as $input) {
  echo preg_replace_callback($pattern, function($x) { return ($x[1]*60+$x[2]).' minutes'; }, $input), "\n";
}

prints

98 minutes
140 minutes

for php versions prior to 5.3 you'd have to use

function foo($x) {
  return ($x[1]*60+$x[2]).' minutes';
}
$pattern = '!(\d+)\s*h\s*(\d+)\s*min!';
foreach( array('1h 38 min', '2h 20 min') as $input) {
  echo preg_replace_callback($pattern, 'foo', $input), "\n";
}

answered Feb 24, 2010 at 2:07

VolkerK

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1 Comment

Jegeg Over a year ago

preg replace gives error Parse error: syntax error, unexpected T_FUNCTION

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