how can i replace date/time in this format 'Fri Mar 23 15:21:08 2012' with preg_replace? Date in this format is present couple of times in my text and i need to replace it with current time/date.
Thanks,
Chris
3 Answers
Well, what you need is an expression that will match 3 letters (Fri) followed by a space and another three letters (Mar).
First we need to match some letters:
/[a-z]/
We can match exactly 3 letters like this:
/[a-z]{3}/
...and we'll need it to be case insensitive:
/[a-z]{3}/i
...so the first part is just:
/[a-z]{3} [a-z]{3}/i
Next, we need to match either 1 or 2 numerics. A numeric can be represented with the escape sequence \d, so we'd use:
/\d{1,2}/
Next we match the time string, using the same escape sequence:
/\d{2}:\d{2}:\d{2}/
...followed by a final 4 digit year:
/\d{4}/
Put it all together and we get:
/[a-z]{3} [a-z]{3} \d{1,2} \d{2}:\d{2}:\d{2} \d{4}/i
// Fri Mar 23 15 : 21 : 08 2012
Now, we need to replace it with the current date and time. The usual place we'd go for that is the date() function, but how to we get that into the replacement dynamically? Well we could pass it as a string literal, or we could use a callback function to get it from preg_replace_callback(). But, preg_replace() gives us the e modifier which causes the replacement string to be evaluated for PHP code. We have to be careful and sparing with it's use, as with any PHP eval(), but this is a legitimate use case.
So our final PHP code looks like this:
preg_replace(
'/[a-z]{3} [a-z]{3} \d{1,2} \d{2}:\d{2}:\d{2} \d{4}/ie',
"date('D M j H:i:s Y')",
$str
);
Comments
I think listing the finite sets of options is kind of better for these task and it will also save you from false positives. These are the patterns to match each part of the date format:
- Days:
(?:Mon|Tue|Wed|Thu|Fri|Sat|Sun) - Months:
(?:Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec) - Day:
\d{1,2} - Time:
\d{1,2}:\d{2}:\d{2} - Year:
\d{4}
Putting everything together:
(?:Mon|Tue|Wed|Thu|Fri|Sat|Sun) (?:Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec) \d{1,2} \d{1,2}:\d{2}:\d{2} \d{4}
The code might look like:
$current_date = date('D M j H:i:s Y');
$text = preg_replace(
'/(?:Mon|Tue|Wed|Thu|Fri|Sat|Sun) (?:Jan|Feb|Mar|Apr|May|Jun|Jul|Aug|Sep|Oct|Nov|Dec) \d{1,2} \d{1,2}:\d{2}:\d{2} \d{4}/i',
$current_date,
$text
);
See a working example.
1 Comment
DaveRandom
I did think about the finite list, but the expression looks so messy I stayed away from it. I think the collision risk in a block of natural language text is so small with a format this complicated that the "match any alpha" approach is acceptable - but +1 for a good working solution.
preg_replace('/Fri Mar 23 15:21:08 2012/',date('D M d H:i:s Y'),$string);
Normally do what you want.
2 Comments
Another Code
The question is how to replace dates in the specified format, not the exact date (which was just an example of the format). If a specific date was to be replaced a simple
str_replace would suffice.
jbrtrnd
Soooo, I must conclude that I've not totally understand the question :) !
str_replace('Fri Mar 23 15:21:08 2012',$newdate,$originaltext);?