Parse error: syntax error, unexpected T_VARIABLE - public variables

Question

Class Config{
public $levels            = 10;
public $points_difference = 100;
public $diff_level        = 3;
public $timer_seconds     = 60;
public $maxBonus          = 0;
public $maxScore          = 0;
public $maxTotalScore     = 0;
public $pointsLevel       = $this->points_difference * $this->diff_level;
}

I get Parse error: syntax error, unexpected T_VARIABLE error on the last line. Any thoughts?

you should write this in constructor. public $pointsLevel = $this->points_difference * $this->diff_level; — Junaid Atique
– Junaid Atique, Commented Apr 25, 2014 at 6:42

fluminis · Accepted Answer · 2014-04-25 06:42:52Z

1

You can't use $this keyword during initialisation.

You need to use a constructor if you need so.

Class Config{
    public $levels            = 10;
    public $points_difference = 100;
    public $diff_level        = 3;
    public $timer_seconds     = 60;
    public $maxBonus          = 0;
    public $maxScore          = 0;
    public $maxTotalScore     = 0;

    public $pointsLevel; //no initialisation here

    function __construct() {
          $this->pointsLevel       = $this->points_difference * $this->diff_level;
    }
}

answered Apr 25, 2014 at 6:42

fluminis

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Comments

user3569839 · Accepted Answer · 2014-04-25 06:46:59Z

0

You cannot use $this on property's
Using from following solution:

<?php
class Config
{

    public $levels            = 10;
    public $points_difference = 100;
    public $diff_level        = 3;
    public $timer_seconds     = 60;
    public $maxBonus          = 0;
    public $maxScore          = 0;
    public $maxTotalScore     = 0;
    public $pointsLevel;

    public function __construct()
    {
        $this->$pointsLevel = $this->points_difference * $this->diff_level;
    }
}

answered Apr 25, 2014 at 6:46

user3569839

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