String into a multi-dimensional array in Ruby?

Question

Really newb question, sorry. I have a string like this made up of several words and want to turn it into an array where each word is a sub array within an array.

my_string = "Made up of several words"
my_array = []
my_string.split(/\s/) do |word|
  my_array << word
end

gives me

["Made", "up", "of", "several", "words"]

but I want to get:

[["Made"], ["up"], ["of"], ["several"], ["words"]]

Anyone know how I can do this please? I'm using the do end syntax because I want a code block where next I can add some logic around what I do with certain words coming in from the string. Thanks.

Arup Rakshit · Accepted Answer · 2014-05-18 10:50:52Z

5

How about below :

my_string = "Made up of several words"
my_string.scan(/(\w+)/) 
# => [["Made"], ["up"], ["of"], ["several"], ["words"]]

answered May 18, 2014 at 10:50

Arup Rakshit

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Comments

Uri Agassi · Accepted Answer · 2014-05-18 16:44:29Z

3

Would this work?

my_string = "Made up of several words"
my_array = my_string.split(/\s+/).map do |word|
  [word]
end
# => [["Made"], ["up"], ["of"], ["several"], ["words"]]

edited May 18, 2014 at 16:44

answered May 18, 2014 at 10:51

Uri Agassi

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2 Comments

arjweb Over a year ago

That was the trick. Putting [ ] around the variable made it come through as an ARRAY as I needed. Thanks

Cary Swoveland Over a year ago

If my_string were "Made up of several words" you would get => [["Made"], ["up"], [""], [""], [""], ["of"], ["several"], ["words"]]. Rather than split(/\s/),I think it would be better to just use split without an argument, which is the same as split(' '), which disregards extra whitespace.

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