I have an multidimensional Array in Ruby, like this:
[["2013-08-22 13:23:12 +0212", 100, 1], ["2013-09-22 14:25:12 +0123" , 123, 1]]
I would like to split the string in the first array position and the time to hours, minutes and seconds (and convert these to integers), so it will become:
[["2013-08-22", 13, 23, 12, "+0212", 100, 1], [.....]]
Does anyone know how to solve this problem?
If you would like more readability, I suggest this:
require 'date'
array = [["2013-08-22 13:23:12 +0212", 100, 1], ["2013-09-22 14:25:12 +0123" , 123, 1]]
array.map do |date_time, a, b|
date_time = DateTime.parse(date_time)
[
date_time.strftime('%F'), date_time.hour, date_time.min,
date_time.sec, date_time.strftime('%z'), a, b
]
end
It makes it very clear what each element of the resulting array is. You should replace a and b with meaningful names if you have them.
"+0212" string. BTW, you need to change every d with date_time. :)
date_time.to_date.to_s as well as date_Time.zone.to_s.gsub(':', ''). Those were two pieces that I didn't really like. It might even be best to pull them out into separate variables before creating the return value.[["2013-08-22 13:23:12 +0212", 100, 1],
["2013-09-22 14:25:12 +0123" , 123, 1]].
map do |arr|
arr.shift.split(/[: ]/) + arr # first position only
# ⇓ this will convert hours, minutes and seconds to integers
# arr.shift.split(/[: ]/).map { |e| e[/\A\d+\z/] ? e.to_i : e } + arr
# ⇓ this would work for all strings
# arr.flat_map { |e| e.is_a?(String) ? e.split(/[: ]/) : e }
end
#⇒ [
# [0] [
# [0] "2013-08-22",
# [1] "13",
# [2] "23",
# [3] "12",
# [4] "+0212",
# [5] 100,
# [6] 1
# ],
# [1] [
# [0] "2013-09-22",
# [1] "14",
# [2] "25",
# [3] "12",
# [4] "+0123",
# [5] 123,
# [6] 1
# ]
# ]
Here's another option (converting hours, minutes and seconds to integers):
arr = [["2013-08-22 13:23:12 +0212", 100, 1], ["2013-09-22 14:25:12 +0123" , 123, 1]]
arr.map do |item|
date, time, zone = item[0].split.map { |e| e.split(":") }
[date, time.map(&:to_i), zone, item[1..-1]].flatten
end
#=> [["2013-08-22", 13, 23, 12, "+0212", 100, 1], ["2013-09-22", 14, 25, 12, "+0123", 123, 1]]
Non-destructive way. ref @mudasobwa answer
arr = [["2013-08-22 13:23:12 +0212", 100, 1], ["2013-09-22 14:25:12 +0123" , 123, 1]]
arr.map {|e| e[0].split(/[ :]/) + e[1..-1] }
#=> [["2013-08-22", "13", "23", "12", "+0212", 100, 1], ["2013-09-22", "14", "25", "12", "+0123", 123, 1]]
arr.map {|e| e[0].split(/[ :]/).map { |e| e[/\A\d+\z/] ? e.to_i : e } + e[1..-1] } to convert hours, minutes and seconds to integer (as requested by OP).