binary '[' : 'std::initializer_list<const char *>' does not define this operator or a conversion to a type acceptable to the predefined operator

Question

How do I access a value from this initializer declared using auto keyword?

auto arr = { "one", "two", "three", "four", "five", "six", "seven", "eight", "nine" };
auto a = arr[0];

Give the following compile-error on VS:

binary '[' : 'std::initializer_list' does not define this operator or a conversion to a type acceptable to the predefined operator

Cubbi · Accepted Answer · 2014-06-21 19:28:41Z

3

Take a look at the interface of std::initializer_list:

auto arr = { "one", "two", "three", "four", "five", "six",
              "seven", "eight", "nine" };
auto a = *arr.begin();

(or, to be more practical, initialize a container or an array with your braced-init-list)

answered Jun 21, 2014 at 19:28

Cubbi

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1 Comment

Jack Over a year ago

That's it. I'm not much used to C++'s way (since I do it much in "C's way") like begin().

4pie0 · Accepted Answer · 2014-06-21 19:33:43Z

2

You can use iterators to traverse the initializer list. Function begin() returns a pointer to the first element in the initializer list.

int main() {

    auto arr = { "one", "two", "three", "four", "five", "six",
              "seven", "eight", "nine" };
    auto a = *arr.begin();
    auto b = *( arr.begin() + 1);

    cout << a << "," << b; // prints: one,two

    return 0;
}

answered Jun 21, 2014 at 19:33

4pie0

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