Hi I have something like:
enum abd {a,b,c};
class d {
private:
abd tab[3][3];
public:
d() {
tab[3][3] = { {a,a,a}, {a,a,a}, {a,a,a} };
}
}
and it yells:
error C2440: '=' : cannot convert from 'initializer-list' to 'abd' and IntelliSense: too many initializer values.
I'm probably blind, cause I cant find my mistake so please tell me whats wrong and how to repair it.
This thing { {a,a,a}, {a,a,a}, {a,a,a} } called initializer list because you can use it only at initialization of array.
abd tab[3][3] = { {a,a,a}, {a,a,a}, {a,a,a} };
class d {
private:
abd tab[3][3];
public:
d() : tab { {a,a,a}, {a,a,a}, {a,a,a}} {}
};
Update
It seems that using
d() : tab { {a,a,a}, {a,a,a}, {a,a,a}} {}
is a problem in VS 2013. See the bug report.
Without support for that, the only choice I can think of is using nested for loops to initialize tab:
d()
{
for ( int i = 0; i < 3; ++i )
for ( int j = 0; j < 3; ++j )
tab[i][j] = a;
}
Arrays have no assignment operators. You could write instead
class d {
private:
abd tab[3][3] = { {a,a,a}, {a,a,a}, {a,a,a} };
public:
d() {
}
};
If the compiler does not support this feature then use some standard algorithm as for example std::fill to assign values to the elements of the array.
For example
#include <algorithm>
enum abd { a, b, d };
class d {
private:
abd tab[3][3];
public:
d() {
std::fill( reinterpret_cast<abd *>( tab ),
reinterpret_cast<abd *>( tab ) + 9,
a );
}
};
i
