JS call to function in php page - syntax issue

Question

HI i tring to call a js function in PHP file using echo ""; and it's not working, if I call it without the echo it's work, what am I missing here ?

this way it's is work:

<a href='#' onClick='delfrmvbar("dlsyg","<?php echo $sgId;?>","<?php echo $sgId;?>")'>X</a>&nbsp;</span>

and this way is not (I tried without the - ' sign)

echo "<a href='#' onClick='delfrmvbar('dlsyg','$sgId','$sgId')'>X</a>&nbsp;</span>";

Why do you pass the same argument twice to your delfrmvbar function? — padarom
– padarom, Commented Jun 27, 2014 at 9:49
I am not, it's just for example, I just forgot to change the name of the third variable. — user3780061
– user3780061, Commented Jun 27, 2014 at 10:10

MrCode · Accepted Answer · 2014-06-27 09:48:55Z

1

Your single quotes are the issue because you use single quotes to wrap the onclick attribute, but then use them again around the arguments.

Example solution: use double quotes around the attribute and escape.

echo "<a href='#' onClick=\"delfrmvbar('dlsyg','$sgId','$sgId')\">X</a>&nbsp;</span>";

This will render the HTML like below, which is syntactically correct:

<a href='#' onClick="delfrmvbar('dlsyg','xx','xx')">X</a>&nbsp;</span>

answered Jun 27, 2014 at 9:48

MrCode

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