Spring com.mongodb.util.JSONParseException

Question

I am trying to execute following query which use a regular expression

BasicQuery b = new BasicQuery("{ description: /\bmanager\b/}");

but it throws com.mongodb.util.JSONParseException

com.mongodb.util.JSONParseException: 
{ description: /manager/}
               ^
    com.mongodb.util.JSONParser.parse(JSON.java:216)
    com.mongodb.util.JSONParser.parseObject(JSON.java:249)
    com.mongodb.util.JSONParser.parse(JSON.java:213)
    com.mongodb.util.JSONParser.parse(JSON.java:163)
    com.mongodb.util.JSON.parse(JSON.java:99)
    com.mongodb.util.JSON.parse(JSON.java:79)

How do I prevent this error

evanchooly · Accepted Answer · 2014-07-18 08:07:27Z

2

The /.../ notation for regex isn't valid json. To use regex in a json document like that you need the form { field: { $regex: 'acme.*corp', $options: 'i' } as shown here.

answered Jul 18, 2014 at 8:07

evanchooly

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