How can I log an exception object with its traceback in Python 3, using the standard logging module?
Note that the exception in question isn't necessarily the one currently being handled.
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2 Answers
Logger objects accept an exc_info argument to include exception information (including traceback), which is expected to be a tuple containing the exception's class, the exception itself and the exception's traceback. The trickiest part is to get hold of the traceback, but it turns out that since Python 3.0, exceptions have a __traceback__ attribute:
logger = logging.getLogger()
exc_info = (type(exc), exc, exc.__traceback__)
logger.error('Exception occurred', exc_info=exc_info)
3 Comments
Lukas Graf
For Python 2.7 you can use
sys.exc_info() to get the traceback of the exception currently being handled.
aknuds1
@LukasGraf I know, but this question deals with general exception objects.
Masood Khaari
You can simply use:
logger.error('Exception occurred', exc_info=exc). Python itself will extract exception type/traceback info.Honestly I don't know if I'm contributing in the slightest by doing this, but I did find this resource that I thought pertinent to your question and I hope useful.
http://www.alexconrad.org/2013/02/loggingexception.html
The gist of it being, if you place logging.exception() inside of an except block, then you can log all of your errors.
1 Comment
aknuds1
The problem is it's not inside an exception handler.