Using urlparse to remove a certain string?

Question

I have this URL:

www.domain.com/a/b/c/d,authorised=false.html

and I want to convert it into

www.domain.com/a/b/c/d.html

Please note I am using python 2.7.

from urlparse import urlparse

url = "www.domain.com/a/b/c/d,athorised=false.html_i_location=http%3A%2F%2Fwww.domain.com%2Fcms%2Fs%2F0%2Ff416e134-2484-11e4-ae78-00144feabdc0.html%3Fsiteedition%3Dintl&siteedition=intl&_i_referer=http%3A%2F%2Fwww.domain.com%2Fhome%2Fus"

o = urlparse(url)
url = o.hostname + o.path
print url

returns www.domain.com/a/b/c/d,authorised=false.html but I don't know how to remove authorised=false part from the URL

@Sushi For future reference, it is easier for people to respond if you include the code inline. — shaktimaan
– shaktimaan, Commented Aug 18, 2014 at 22:58

johntellsall · Accepted Answer · 2014-08-18 22:52:45Z

3

import re
print re.sub(r',.+\.', '.', 'www.domain.com/a/b/c/d,authorised=false.html')

# www.domain.com/a/b/c/d.html

answered Aug 18, 2014 at 22:52

johntellsall

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