strip string from url in Python

Question

input: url = http://127.0.0.1:8000/data/number/

http://127.0.0.1:8000/data/ is consistent for each page number.

output: number

Instead of slicing the url url[-4:-1], Is there any better way to do it?

Split at /, find index of "data" and take everything from that index on, if you want to allow for multiple things after it. But why do you want to avoid slicing? I think you're going to end up doing it at some phase anyway, I don't see how you can cut anything out from a larger thing without slicing. — user1425689
– user1425689, Commented Jun 4, 2015 at 17:52

Andy · Accepted Answer · 2015-06-04 17:54:59Z

2

You can use a combination of urlparse and split.

import urlparse
url = "http://127.0.0.1:8000/data/number/"
path = urlparse.urlparse(url).path
val = path.split("/")[2]
print val

This prints:

number

The output of urlparse for the above URL is

ParseResult(scheme='http', netloc='127.0.0.1:8000', path='/data/number/', params='', query='', fragment='')

We are utilizing the path portion of this tuple. We split it on / and take the second index.

answered Jun 4, 2015 at 17:54

Andy♦

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Comments

duck · Accepted Answer · 2015-06-04 17:54:46Z

2

use urlparse module life would be easier

from urlparse import urlparse
urlparse('http://127.0.0.1:8000/data/number/').path.split('/')[2]

answered Jun 4, 2015 at 17:54

duck

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