PHP 'foreach' array concatenate echo

Question

The following will echo "12334".

However, I would like for the "12334" to be placed in a variable say $wordNumValue. I know it might be a simple thing, but to me it is not. Any help is much appreciated.

<?php
$msg ="hello";
$arrEn = str_split($msg);
foreach ($arrEn as &$value) {
    if ($value == 'h') {
          echo "1";
        } elseif ($value == 'e') {
          echo "2";
        } elseif ($value == 'l') {
          echo "3";
        } elseif ($value == 'o') {
          echo "4";
        } else {
          echo 'NULL';
        } 
}
?>

If it helps you can accept the best answer..

Sky
– Sky

2014-09-28 22:48:50 +00:00
Commented Sep 28, 2014 at 22:48 — Sky
– Sky, Commented Sep 28, 2014 at 22:48

derdida · Accepted Answer · 2014-09-28 22:34:31Z

2

<?php
$msg ="hello";
$arrEn = str_split($msg);
$wordNumValue = "";
foreach ($arrEn as &$value) {
if ($value == 'h') {
      echo "1";
      $wordNumValue .= "1";
    } elseif ($value == 'e') {
      echo "2";
      $wordNumValue .= "2";
    } elseif ($value == 'l') {
      echo "3";
      $wordNumValue .= "3";
    } elseif ($value == 'o') {
      echo "4";
      $wordNumValue .= "4";
    } else {
      echo 'NULL';
    } 
}
?>

answered Sep 28, 2014 at 22:34

derdida

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Comments

Sky · Accepted Answer · 2014-09-28 22:42:09Z

Try this:

<?php
$msg ="hello";
$arrEn = str_split($msg);
$wordNumValue = '';
foreach ($arrEn as &$value) {
    if ($value == 'h') {
        echo "1";
        $wordNumValue .= "1";
    } elseif ($value == 'e') {
        echo "2";
        $wordNumValue .= "2";
    } elseif ($value == 'l') {
        echo "3";
        $wordNumValue .= "3";
    } elseif ($value == 'o') {
        echo "4";
        $wordNumValue .= "4";
    } else {
        echo 'NULL';
    }
}

But as you have many elseifs I, would do this instead:

<?php
$msg ="hello";
$arrEn = str_split($msg);
$wordNumValue = '';
foreach ($arrEn as &$value) {
    switch ($value) {
        case "h":
            $wordNumValue .= "1";
            break;
        case "e":
            $wordNumValue .= "2";
            break;
        case "l":
            $wordNumValue .= "3";
            break;
        case "o":
            $wordNumValue .= "4";
            break;
        default:
            echo 'NULL';
    }
}
echo $wordNumValue;

And finally I echoed $wordNumValue instead of echoing single numbers several times.

worldofjr · Accepted Answer · 2014-09-28 22:42:12Z

1

You can add each string onto a variable using the .= assignment operator;

<?php
$msg ="hello";
$arrEn = str_split($msg);
foreach ($arrEn as &$value) {
    if ($value == 'h') {
          $wordNumValue .= "1";
        } elseif ($value == 'e') {
          $wordNumValue .= "2";
        } elseif ($value == 'l') {
          $wordNumValue .= "3";
        } elseif ($value == 'o') {
          $wordNumValue .= "4";
        }
}
?>

You don't need the final else. See this, PHP: Assignment Operators, and this, PHP: String Operators.

Hope this helps.

edited Sep 28, 2014 at 22:42

answered Sep 28, 2014 at 22:36

worldofjr

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1 Comment

worldofjr Over a year ago

Hi @Hemn Baker, if this or any answer has solved your question please consider accepting it by clicking the check-mark. This indicates to the wider community that you've found a solution and gives some reputation to both the answerer and yourself. There is no obligation to do this.

BojanT · Accepted Answer · 2014-09-28 23:02:21Z

-1

You don't need to change your code , before foreach add ob_start(); and after foreach add $wordNumValue = ob_get_clean();

answered Sep 28, 2014 at 23:02

BojanT

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1 Comment

worldofjr Over a year ago

That is possibly the biggest sledgehammer I've ever seen to crack the smallest nut in existence.

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