Concatenate array on loop php

Question

I have this array

[0] => Array
        (
            [0] => My name
            [1] => is
            [2] => John
        )

[1] => Array
        (
            [0] => My name is Jane
        )

how to achieve this kind of output see below. If the array count is greater than one I want to combine them as one.

[0] => Array
        (
            [0] => My name is John
        )

[1] => Array
        (
            [0] => My name is Jane
        )

here is my code but it didn't work

foreach ($myArr as $key => $value) {
    if (count($myArr[$key]) > 1) {
        foreach ($value as $k => $v) {
            $myArr[$key] .= $v; 
        }
    }
}

thanks

I got this error @AmitMerchant Notice: Array to string conversion — pal3
– pal3, Commented Feb 10, 2018 at 4:10

sorak · Accepted Answer · 2018-02-10 04:15:40Z

2

Why not use implode?

$data = [['my name', 'is', 'John'],['my name is Jane']];
$results = [];
foreach ($data AS $id=>$datum)
    if (count($datum) > 1)
        $results[$id] = implode($datum, ' ');
    else
        $results[$id] = $datum[0];

results:

array(2) {
  [0]=>
  string(15) "my name is John"
  [1]=>
  string(15) "my name is Jane"
}

answered Feb 10, 2018 at 4:15

sorak

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7 Comments

Amit Merchant Over a year ago

Thumbs up for using implode().

Antonio De Rose Over a year ago

Nice, should work with normal array too, does seem like associative array is redundant.

Antonio De Rose Over a year ago

``` <?php $data = [['my nameJohn'],['my name is Jassadasdsadsadane']]; $results = []; foreach ($data AS $datum) if (count($datum) > 1) $results[] = implode($datum, ' '); else $results[] = $datum[0]; echo "<pre>"; print_r($results); echo "</pre>";

sorak Over a year ago

My code was just storing the results in the same key as the source. Because the source is a numerically-indexed array, you could theoretically ditch the [$id] assignment, but it's no slower and will inherently respect arbitrary key values, which could be relevant if you had filtered the source array for some reason to remove some entries, or had string keys

Nishanth Matha Over a year ago

$results is still the same as in OP. Op did not use any associative array

|

Amit Merchant · Accepted Answer · 2018-02-10 04:18:56Z

1

I suppose it would be like this:

foreach ($myArr as $key => $value) {
    if (count($myArr[$key]) > 1) {
        $myArr[$key][0] = '';  
        foreach ($value as $k => $v) {
            $myArr[$key][0] .= $v; 
        }
        array_splice($myArr[$key], 1, count($myArr[$key])-1);
    }
}

edited Feb 10, 2018 at 4:18

answered Feb 10, 2018 at 4:10

Amit Merchant

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5 Comments

pal3 Over a year ago

the output would be the same

Amit Merchant Over a year ago

Did you check it?

pal3 Over a year ago

Yes I checked it

Amit Merchant Over a year ago

For me It's working: sandbox.onlinephpfunctions.com/code/…

Antonio De Rose Over a year ago

<?php $data = [['my nameJohn'],['my name is Jassadasdsadsadane']]; $results = []; foreach ($data AS $datum) if (count($datum) > 1) $results[] = implode($datum, ' '); else $results[] = $datum[0]; echo "<pre>"; print_r($results); echo "</pre>";

Muhammed Rafi .K.A · Accepted Answer · 2018-02-10 05:41:00Z

1

I suppose it would be like this:

$ary[0] = Array("My name","is","John");
$ary[1] = Array( "My name is Jane" );
$i=0;       
foreach ($ary as $ar_item)  {
    $merged="";
foreach  ($ar_item as $ar_subitem)  
{
    $merged=$merged.$ar_subitem." ";
}
$ary[$i]=$merged;
$i++;
}
var_dump($ary);

edited Feb 10, 2018 at 5:41

answered Feb 10, 2018 at 4:30

Muhammed Rafi .K.A

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