Passing Variables through Functions in JavaScript

Question

I am trying to make it where if one function runs and defines the variable the other function will be able to reconize the function. I'm a little new to Javascript so my code may be just a bunch of jibberish.

function next() {
    var random = Math.floor(Math.random() * 15)
    document.getElementById("image").src = picture[random];
    console.log(random);
}

function who() {
    var thing = things[random];
    var text = document.getElementById("am").innerHTML = "I am " + thing + ".";
    console.log(text);
}

KyleK · Accepted Answer · 2014-10-24 09:02:03Z

2

Like this:

var random;

function next() {
    random = Math.floor(Math.random() * 15);
    document.getElementById("image").src = picture[random];
    console.log(random);
}

function who() {
    var thing = things[random];
    var text = document.getElementById("am").innerHTML = "I am " + thing + ".";
    console.log(text);
}

edited Oct 24, 2014 at 9:02

answered Oct 23, 2014 at 21:52

KyleK

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2 Comments

carlosherrera Over a year ago

Yes. I think this is better than mine because everytime next() is used, random will change.

Jeremy Vidaurri Over a year ago

I tried that but for some reason it says "I am undefined." I had defined the variable things defined earlier. For all my code go link

carlosherrera · Accepted Answer · 2014-10-23 21:52:32Z

0

Define the random variable first, and then send it to the functions, like this;

var random = Math.floor(Math.random() * 15);

next(random);
who(random);

function next(random) {

    document.getElementById("image").src = picture[random];
    console.log(random);
}

function who(random) {
    var thing = things[random];
    var text = document.getElementById("am").innerHTML = "I am " + thing + ".";
    console.log(text);
}

answered Oct 23, 2014 at 21:52

carlosherrera

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1 Comment

Jeremy Vidaurri Over a year ago

But then random won't change I need it to change every time I run next()

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