Convert IP address string to binary in Python

Question

As part of a larger application, I am trying to convert an IP address to binary. Purpose being to later calculate the broadcast address for Wake on LAN traffic. I am assuming that there is a much more efficient way to do this then the way I am thinking. Which is breaking up the IP address by octet, adding 0's to the beginning of each octet where necessary, converting each octet to binary, then combining the results. Should I be looking at netaddr, sockets, or something completely different?

Example: From 192.168.1.1 to 11000000.10101000.00000001.00000001

Are you looking to convert an IPv4 Address into its integer representation? Or what binary representation are you trying to convert to? — Nate
– Nate, Commented Apr 28, 2010 at 23:28
Example: From 192.168.1.1 to 11000000.10101000.00000001.00000001 — pizzim13
– pizzim13, Commented Apr 28, 2010 at 23:35
That is an extremely uncommon way to express ipaddresses. I don't think any module exists to produce or consume that format. — Thomas Wouters
– Thomas Wouters, Commented Apr 29, 2010 at 0:00
The way you are thinking of is perfectly good and efficient enough, IMHO. — ktdrv
– ktdrv, Commented Apr 29, 2010 at 0:24

kriss · Accepted Answer · 2010-04-29 13:54:07Z

9

You think of something like below ?

ip = '192.168.1.1'
print '.'.join([bin(int(x)+256)[3:] for x in ip.split('.')])

I agree with others, you probably should avoid to convert to binary representation to achieve what you want.

answered Apr 29, 2010 at 13:54

kriss

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3 Comments

pizzim13 Over a year ago

That's what I was looking for but, I don't fully understand how it works. I get that you are splitting the ip address by '.', then joining the results by a '.', and converting from a integer to binary but this: "(x)+256)[3:] for x in", completely lost. Can you point in the right direction to look up what you are doing?

kriss Over a year ago

@pizzim13: no magick. You understood well how it works. The +256 is there to always have a 9 bits binary number, then it's easy to remove 0b1 at front of the number.

kriss Over a year ago

@pizzim13: and for the [... for x in ... ] part look at list comprehension in python documentation.

EMP · Accepted Answer · 2010-04-28 23:30:06Z

9

Is socket.inet_aton() what you want?

answered Apr 28, 2010 at 23:30

EMP

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1 Comment

jfs Over a year ago

It seems to work: bin(struct.unpack('!I', socket.inet_aton('192.168.1.1'))[0]) -> '0b11000000101010000000000100000001'

jfs · Accepted Answer · 2013-11-08 09:55:40Z

9

Purpose being to later calculate the broadcast address for Wake on LAN traffic

ipaddr (see PEP 3144):

import ipaddr

print ipaddr.IPNetwork('192.168.1.1/24').broadcast
# -> 192.168.1.255

In Python 3.3, ipaddress module:

#!/usr/bin/env python3
import ipaddress

print(ipaddress.IPv4Network('192.162.1.1/24', strict=False).broadcast_address)
# -> 192.168.1.255

To match the example in your question exactly:

# convert ip string to a binary number
print(bin(int(ipaddress.IPv4Address('192.168.1.1'))))
# -> 0b11000000101010000000000100000001

edited Nov 8, 2013 at 9:55

answered Apr 29, 2010 at 0:09

jfs

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Comments

Danilo · Accepted Answer · 2016-04-06 15:57:49Z

3

You can use string format function to convert the numbers to binary. I made this function:

def ip2bin(ip):
    octets = map(int, ip.split('/')[0].split('.')) # '1.2.3.4'=>[1, 2, 3, 4]
    binary = '{0:08b}{1:08b}{2:08b}{3:08b}'.format(*octets)
    range = int(ip.split('/')[1]) if '/' in ip else None
    return binary[:range] if range else binary

This will return a binary IP or IP range, so you can use it to test if an IP is in a range:

>>> ip2bin('255.255.127.0')
'11111111111111110111111100000000'
>>> ip2bin('255.255.127.0/24')
'111111111111111101111111'
>>> ip2bin('255.255.127.123').startswith(ip2bin('255.255.127.0/24'))
True

answered Apr 6, 2016 at 15:57

Danilo

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Comments

jwpfox · Accepted Answer · 2017-12-21 03:28:24Z

1

Define IP address in variable

ipadd = "10.10.20.20"

convert IP address in list

ip = ipadd.split(".")

Now convert IP address in binary numbers

print ('{0:08b}.{1:08b}.{2:08b}. 
    {3:08b}'.format(int(ip[0]),int(ip[1]),int(ip[2]),int(ip[3])))

00001010.00001010.00010100.00010100

edited Dec 21, 2017 at 3:28

jwpfox

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answered Dec 21, 2017 at 3:24

Devendra Singh

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Comments

Ahmed · Accepted Answer · 2019-01-29 16:04:50Z

1

IP = '192.168.1.1'

ip2bin =  ".".join(map(str,["{0:08b}".format(int(x)) for x in IP.split(".")]))
print(ip2bin)

output

11000000.10101000.00000001.00000001

answered Jan 29, 2019 at 16:04

Ahmed

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Comments

Eron Lloyd · Accepted Answer · 2022-07-19 01:45:42Z

1

Should I be looking at netaddr, sockets, or something completely different?

For anyone asking in the present day, you should use netaddr if you want to do anything not supported in the Python 3.3+ built-in ipaddress module. Here is how you would do what you wanted to with netaddr, as an example:

>>> from netaddr import IPAddress
>>> ip = IPAddress('192.168.1.1')
>>> print(ip.bits())
11000000.10101000.00000001.00000001

answered Jul 19, 2022 at 1:45

Eron Lloyd

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Comments

Mythily Thangavelu · Accepted Answer · 2022-06-01 05:12:24Z

0

ip = '192.168.1.1'

k=[" "]

for x in ip.split("."):

   a=(bin(int(x))[2:])
   k.append(a)

print(".".join(list(k))[2:])

answered Jun 1, 2022 at 5:12

Mythily Thangavelu

1

1 Comment

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