How can I use python .format() to take an unsigned binary integer and output an ip address/netmask? For example,
print("Netmask {...} ".format('10001000100010001000100010001000'))
10001000.10001000.10001000.10001000
1 Answer
You can use your input, bitshift it after masking and put it back together:
number = int('10001000100010001000100010001000',2)
one = number & 0xff
two = (number & 0xff00) >> 8
three = (number & 0xff0000) >> 16
four = (number & 0xff000000) >> 24
print(f"{four}.{three}.{two}.{one}")
print(f"{four:b}.{three:b}.{two:b}.{one:b}")
Output
136.136.136.136 # as normal int
10001000.10001000.10001000.10001000 # as binary int
You can use "{:b}.{:b}.{:b}.{:b}".format(four,three,two,one) instead of f-strings if you are below 3.6.
Disclaimer: this uses Python int to binary string? applied to some binary bitshiftiness:
10001000100010001000100010001000 # your number
& 11111111000000000000000000000000 # 0xff000000
= 10001000000000000000000000000000 # then >> 24
10001000
10001000100010001000100010001000 # your number
& 00000000111111110000000000000000 # 0xff0000
= 00000000100010000000000000000000 # then >> 16
0000000010001000 # etc.
socket.inet_ntoa(struct.pack('!L', int('10001000100010001000100010001000', 2)))'{}.{}.{}.{}'.format(s[:8], s[8:18], s[16:24], s[24:])what you want?