PHP display image without HTML

Question

How may I display an image without using any kind of HTML.

Let's say I have some protected images, which may only be shown to some users. The protected image is in directory images/protected/NoOneCanViewMeDirectly.png

Then we have a PHP file in the directory images/ShowImage.php, which check if the user is permitted to view the image.

How may I display the image using PHP only.

If you're not sure what I mean this is how I want to display the image. http://gyazo.com/077e14bc824f5c8764dbb061a7ead058

The solution is not echo '<img src="images/protected/NoOneCanViewMeDirectly.png">';

How exactly isn't this a question? "How may I display the image using PHP only." — Kaare
– Kaare, Commented Dec 29, 2014 at 11:52
@Kaare Actually, this question's been asked before. You just needed to Google your question's title. You've not shown us what you tried. You only mention/asked "how". — Funk Forty Niner
– Funk Forty Niner, Commented Dec 29, 2014 at 11:54

KhorneHoly · Accepted Answer · 2014-12-29 11:47:20Z

4

You could just header out the image with the following syntax

header("Content-type: image/png");
echo file_get_contents(__DIR__."/images/protected/NoOneCanViewMeDirectly.png");

answered Dec 29, 2014 at 11:47

KhorneHoly

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6 Comments

Ziumin Over a year ago

1) Content type should be image/png for png files 2) better use readfile(...)

Kaare Over a year ago

Thank you. That was what I searched for.

vladkras Over a year ago

image/jpg and .png?

KhorneHoly Over a year ago

I didn't noticed the png, edited it into the answer. Never worked with readfile, so I don't know if it's better or not, but it works for me

vladkras Over a year ago

also __DIR__ will return you current location of script file, not root directory, so if you have this code in say /modules/images/functions.php your image path will be /modules/images/iamges/protected/...

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Community · Accepted Answer · 2017-05-23 12:20:34Z

2

if (<here your logic to show file or not>)
    $path = $_SERVER["DOCUMENT_ROOT"].<path_to_your_file>; // to get it correctly
    $ext = explode(".", $path);
    header("Content-Type: image/".array_pop($ext)); // correct MIME-type
    header('Content-Length: ' . filesize($path)); // content length for most software
    readfile($path); // send it
}

Note: 1. image/jpg is not correct MIME-type, use image/jpeg instead (additional check needed), 2. readlfile() is better than echo file_get_contents() for binary data, 3. always try to provide content length for browsers and other software

edited May 23, 2017 at 12:20

CommunityBot

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answered Dec 29, 2014 at 11:57

vladkras

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Comments

Justinas · Accepted Answer · 2014-12-29 11:48:33Z

-1

You can use imagepng to output png image to browser:

$im = imagecreatefrompng("images/protected/NoOneCanViewMeDirectly.png");

header('Content-Type: image/png');

imagepng($im);
imagedestroy($im);

answered Dec 29, 2014 at 11:48

Justinas

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