php : display image resource

Question

I feel quite stupid but I can't understand how to display the output of the imagepng() function.

What I currently do is (and it works fine) :

<img src=<?php echo getImage($element); ?> />

function getImage($element){
    return $bdd[$element]; // the result is a string with the path to the image
}

But I would love to draw some circles on the image, so here is what I would like to do (and it does not work) :

<img src=<?php echo getImage($element); ?> />

function getImage($element){
    $image = imagecreatefrompng($bdd[$element]);
    $ellipseColor = imagecolorallocate($image, 0, 0, 255);
    imagefilledellipse($image, 100, 100, 10, 10, $ellipseColor);
    imagepng($image);

    return $image // why does that image resource not display ?
}

But it does not display anything else than symbols.. I assume it returns a full image and not a path to the image.. so How should I display my image with the circle on it ?

ps : I also tried to create a page getImage.php that would be called by <img src=<?php echo 'getImage.php?element=' . $element; ?> /> but with no success

what is the result here: Just read the Manual page, php.net/manual/en/function.imagepng.php, this function returns bool, true/false. — pavel
– pavel, Commented May 20, 2015 at 16:08
@Arcyno: $image is resource: php.net/manual/en/function.imagecreatefrompng.php — pavel
– pavel, Commented May 21, 2015 at 7:35
Actually I read that. Let's rephrase my question : how can I display this resource on my website ? — Arcyno
– Arcyno, Commented May 21, 2015 at 7:36

Dave Plug · Accepted Answer · 2015-05-21 08:28:47Z

3

You have to do something like this

<img src="image.php">

And in the image.php you use your code

$image = imagecreatefrompng($bdd[$element]);
$ellipseColor = imagecolorallocate($image, 0, 0, 255);
imagefilledellipse($image, 100, 100, 10, 10, $ellipseColor);
imagepng($image);

answered May 21, 2015 at 8:28

Dave Plug

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3 Comments

Jose Manuel Abarca Rodríguez Over a year ago

I didn't know a PHP file could be used as "src=" (+1), first time I see this. For those who can't make "image.php" to work, I made it work by adding ob_start(); at the beginning and ob_end_flush(); and ob_end_clean(); at the end (just before imagepng($image);).

Meryan Over a year ago

@JoseManuelAbarcaRodríguez could please give reference not docs how did you guessed or found about these ob_XXX() calls, because it's been a whole day of grief, trying different thumbnail creator codes that did not want to display this image resource. thanks

Jose Manuel Abarca Rodríguez Over a year ago

@Meryem, try this answer ► stackoverflow.com/a/3695085/3298930

Arcyno · Accepted Answer · 2015-05-21 08:26:04Z

1

I finally got my answer on how to display the image inside an HTML page : I need to put the code in another file displayImage.php and make a call to this page from the <img>tag :

Main file with html tag:

<img src="displayImage.php?element='<?php echo $element; ?> />

displayImage.php :

<?php

header('Content-Type: image/png');
$image = imagecreatefrompng($bdd[$element]);
$ellipseColor = imagecolorallocate($image, 0, 0, 255);
imagefilledellipse($image, 100, 100, 10, 10, $ellipseColor);
imagepng($image);
imagedestroy( $image );

?>

answered May 21, 2015 at 8:26

Arcyno

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