Attempting to replace character value in dataframe with numeric value , Error " invalid factor level, NA generated"

Question

I’m trying to do some that preprocessing, and want to convert the classe factors values {A,B,C,D,E} to {1,2,3,4,5}.

The classe column is of type factor, I have provided all steps, see below:

    #get the data
    training <- read.table("http://d396qusza40orc.cloudfront.net/predmachlearn/pml-training.csv",header=TRUE, sep=",", na.strings="NA", dec=".", strip.white=TRUE)
    training_df <- data.frame(training,stringsAsFactors=FALSE)

    #split to training & test sets
    inTrain <- createDataPartition(y=training$classe, p=0.75, list=FALSE)
    training_data <- training[inTrain,]
    testing_data <- training[-inTrain,]

    #subset based on columns of interest, based on previous studies
    training_data_subset <- subset(training_data, select=c("avg_roll_belt","var_roll_belt","var_total_accel_belt","amplitude_roll_belt","max_roll_belt","var_roll_belt",
    "var_accel_arm","magnet_arm_x","magnet_arm_y","magnet_arm_z","accel_dumbbell_y","accel_dumbbell_z","magnet_dumbbell_x","gyros_dumbbell_x",
    "gyros_dumbbell_y","gyros_dumbbell_z","pitch_forearm","gyros_forearm_x","gyros_forearm_y","classe"))

    #see which columns are factors, the training_data_subset#classe feature is a factor
    sapply(training_data_subset, class)

#sapply output

 avg_roll_belt        var_roll_belt var_total_accel_belt  amplitude_roll_belt        max_roll_belt 
           "numeric"            "numeric"            "numeric"            "numeric"            "numeric" 
     var_roll_belt.1        var_accel_arm         magnet_arm_x         magnet_arm_y         magnet_arm_z 
           "numeric"            "numeric"            "integer"            "integer"            "integer" 
    accel_dumbbell_y     accel_dumbbell_z    magnet_dumbbell_x     gyros_dumbbell_x     gyros_dumbbell_y 
           "integer"            "integer"            "integer"            "numeric"            "numeric" 
    gyros_dumbbell_z        pitch_forearm      gyros_forearm_x      gyros_forearm_y               classe 
           "numeric"            "numeric"            "numeric"            "numeric"             "factor"

I created a function that attempts to replace A=1,B=2,C=3,D=4,E=5, see below:

factorsToNumeric <- function(data)
{
    data_numeric <- data
    data_numeric$classe <-as.numeric(factor(toupper(as.character(data_numeric$classe))))
    #loop through the data frame based on replace values
    for(i in 1:nrow(data_numeric)) 
    {

    if ((data_numeric[i,]$classe == "A") || (data_numeric[i,]$classe  == "a")) 
    {data_numeric[i,]$classe <- "1"}
    else if ((data_numeric[i,]$classe  == "B") || (data_numeric[i,]$classe  == "b"))
    {data_numeric[i,]$classe <- "2"}
    else if ((data_numeric[i,]$classe  == "C") || (data_numeric[i,]$classe  == "c"))
    {data_numeric[i,]$classe <- "3"}
    else if ((data_numeric[i,]$classe  == "D") || (data_numeric[i,]$classe  == "d"))
    {data_numeric[i,]$classe <- "4"}
    else if ((data_numeric[i,]$classe  == "E") || (data_numeric[i,]$classe  == "e"))
    {data_numeric[i,]$classe <- "5"}
    else 
    {
    #do nothing 
    }

    }

    return (data_numeric)
}

However, I get this error:

training_data_subset_numeric <- factorsToNumeric(training_data_subset)

Error:

Warning messages:
1: In `[<-.factor`(`*tmp*`, iseq, value = "1") :
  invalid factor level, NA generated
2: In `[<-.factor`(`*tmp*`, iseq, value = "1") :
  invalid factor level, NA generated
3: In `[<-.factor`(`*tmp*`, iseq, value = "1") :
  invalid factor level, NA generated
4: In `[<-.factor`(`*tmp*`, iseq, value = "1") :
  invalid factor level, NA generated
5: In `[<-.factor`(`*tmp*`, iseq, value = "1") :
  invalid factor level, NA generated
6: In `[<-.factor`(`*tmp*`, iseq, value = "1") :
  invalid factor level, NA generated
7: In `[<-.factor`(`*tmp*`, iseq, value = "1") :
  invalid factor level, NA generated
8: In `[<-.factor`(`*tmp*`, iseq, value = "1") :
  invalid factor level, NA generated
9: In `[<-.factor`(`*tmp*`, iseq, value = "1") :
  invalid factor level, NA generated

Further inspection shows the column "classe"'s class is converted to "numeric":

 sapply(training_data_subset_numeric, class)

 avg_roll_belt        var_roll_belt var_total_accel_belt  amplitude_roll_belt        max_roll_belt 
       "numeric"            "numeric"            "numeric"            "numeric"            "numeric" 
 var_roll_belt.1        var_accel_arm         magnet_arm_x         magnet_arm_y         magnet_arm_z 
       "numeric"            "numeric"            "integer"            "integer"            "integer" 
accel_dumbbell_y     accel_dumbbell_z    magnet_dumbbell_x     gyros_dumbbell_x     gyros_dumbbell_y 
       "integer"            "integer"            "integer"            "numeric"            "numeric" 
gyros_dumbbell_z        pitch_forearm      gyros_forearm_x      gyros_forearm_y               classe 
       "numeric"            "numeric"            "numeric"            "numeric"            "numeric"

However, the head function confirms the error above & all the values A,B,C,D,E have been replaced with NA incorrectly.

You could try the following approach training_data_subset$classe <- as.numeric(factor(toupper(as.character(training_data_subset$classe)))) — talat
– talat, Commented Jan 3, 2015 at 0:55
@docendo discimus, I added the correct variation of your suggestion at the beginning of the factorsToNumeric() function and it worked, see edited post. — cyber101
– cyber101, Commented Jan 3, 2015 at 7:40
You misunderstood. That code should replace replace the function. — talat
– talat, Commented Jan 3, 2015 at 7:58

Rich Scriven · Accepted Answer · 2015-01-03 08:50:20Z

Factors don't work like that. You can't change values with simple <- assignment like other data types. There are a few different ways you can change a factor. Here's one way using the levels<- replacement function.

Here's a sample from your enormous data that took way too long to read :) For this data it's easy because the levels are in the right sequential order already.

set.seed(2)
x <- sample(training$classe, 20)
x
# [1] A D C A E E A E B C C A D A B E E A B A
# Levels: A B C D E
levels(x) <- 1:5
x
# [1] 1 4 3 1 5 5 1 5 2 3 3 1 4 1 2 5 5 1 2 1
# Levels: 1 2 3 4 5

So there's no need for your function. You can simply do

levels(training$classe) <- 1:5

and we can see the str of the new column shows the changed values

str(training$classe)
# Factor w/ 5 levels "1","2","3","4",..: 1 1 1 1 1 1 1 1 1 1 ...

Note that for this simple case, as.integer(training$classe) also works. Although it won't be that easy most of the time.

CephBirk · Accepted Answer · 2015-01-03 00:52:37Z

0

If you want to convert the classe column of training_data_subset you don't need to define your own function. You can use the LETTERS vector:

sapply(training_data_subset[,'classe'], function(x) which(LETTERS==x))

answered Jan 3, 2015 at 0:52

CephBirk

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