Using Arrays For Function Input Argument

Question

I'm trying to use an array for function's input argument, when I call this function with a manual value, the function works good, but when I use an array with that value instead of the manual value, my function doesn't work correctly.

Example of my code:

Search("FileName","Word");
----------------------
Search("NotePad1","Hello"); >>> Work Correctly!
----------------------
But:
--------------------

char Word[25]={'H','e','l','l','o'};

Search("NotePad1",Word); >>>Doesn't Work! :-(
--------------------

try char Word[25]={'H','e','l','l','o','\0'};

KNU
– KNU

2015-01-19 06:37:23 +00:00
Commented Jan 19, 2015 at 6:37 — KNU
– KNU, Commented Jan 19, 2015 at 6:37
having a function declaration may be useful to see.

user1269942
– user1269942

2015-01-19 06:37:41 +00:00
Commented Jan 19, 2015 at 6:37 — user1269942
– user1269942, Commented Jan 19, 2015 at 6:37

laalto · Accepted Answer · 2015-01-19 06:36:06Z

2

String literals such as "Hello" also include the NUL terminator byte at the end.

Add the terminator to your array as well:

char Word[25]={'H','e','l','l','o', 0};

Otherwise the C string read from the array will also contains any junk data at the end of the array and memory locations after it, up to the next zero byte in memory.

answered Jan 19, 2015 at 6:36

laalto

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user1269942 · Accepted Answer · 2015-01-19 06:39:18Z

0

what about:

char* Word = "Hello";

depends on how you declared your function.

answered Jan 19, 2015 at 6:39

user1269942

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Comments

KNU · Accepted Answer · 2015-01-19 07:29:40Z

0

Assuming the function declaration to be as

boolean Search(String Filename ,String word);

try

char Word[]={'H','e','l','l','o','\0'}; // <- NULL terminated , a well formed string
Search("NotePad1" , Word);

It is because String in C/C++ and null terminated.

Conclusion :

If you are passing char array where argument expects a String make sure the char array is null terminated or pass string as "this".

answered Jan 19, 2015 at 7:29

KNU

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