Ruby refactoring issue

Question

Let's say I have an @array = [1 ,2 ,3] I want to create three blocks of each number of the array with the rest like this :

@array.each do |first|
  (@array - [first]).each do |second|
    (@array - [first] - [second]) do |third|
      #do something

So each block iterates through the entire array except the element that's being used by the preceding block. But this is kind of smelly and repetitive, because for each block I need to delete the preceding elements , what is the best way to refactor these blocks?

Thanks

Max answered me, looks like it' clear what I am asking to some people. — Ahmad Al-kheat
– Ahmad Al-kheat, Commented Feb 4, 2015 at 23:03

Max · Accepted Answer · 2015-02-04 23:05:56Z

2

The terminology for that is a permutation. Ruby has a built-in method for doing so:

@array.permutation(3) do |first, second, third|
  # do something
end

edited Feb 4, 2015 at 23:05

answered Feb 4, 2015 at 23:00

Max

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1 Comment

Ahmad Al-kheat Over a year ago

Thank you very much Max, this is what I am looking for. Will accept once I can

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