php string not working properly

Question

My code in php is

echo $preference[0]."</br>";
echo '<p class="filter_entity">'.$preference[0].'<img src="' . base_url() . 'images/close-icon.png" onClick="filter_close()"></p>';

html out put is

Business
<img onclick="filter_close()" src="http://localhost/AEC/images/close-icon.png">

I want to put $preference[0] in filter_close() of my php code ... dont know how to do it .

onClick="filter_close('.$preference[0].') like this??

coDe murDerer
– coDe murDerer

2015-02-09 12:11:23 +00:00
Commented Feb 9, 2015 at 12:11 — coDe murDerer
– coDe murDerer, Commented Feb 9, 2015 at 12:11
Are you sure it is html output of this code ?

Mikrobi
– Mikrobi

2015-02-09 12:15:55 +00:00
Commented Feb 9, 2015 at 12:15 — Mikrobi
– Mikrobi, Commented Feb 9, 2015 at 12:15

Phate01 · Accepted Answer · 2015-02-09 12:12:47Z

1

Something like this?

$param = $preference[0];
echo '<p class="filter_entity">'.$preference[0].'<img src="' . base_url() . 'images/close-icon.png" onClick="filter_close(\''.echo $param.'\')"></p>';

Just append the variable as a parameter of the js function

answered Feb 9, 2015 at 12:12

Phate01

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2 Comments

Phate01 Over a year ago

What do you want to pass to a php variable?

Vipul sharma Over a year ago

i did it like this ,,, your solution worked onClick="filter_close(\''.$filter_name.'\',\''.$preference[2].'\')"

Sergey Chizhik · Accepted Answer · 2015-02-09 12:25:07Z

0

http://php.net/manual/en/language.types.string.php#language.types.string.syntax.double

echo "Some array item: {$array[0]}";

edited Feb 9, 2015 at 12:25

answered Feb 9, 2015 at 12:19

Sergey Chizhik

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