Zend rpc json return array

Question

Hi there I have a small problem i can't figure out. Im writing a RPC service using ZendFramework and Apigility. The response must be a json array. Next comes all the content negotiation code.

'controllers' => array(
        'NmdaWebApi\\V1\\Rpc\\Hola\\Controller' => 'Json',

'accept_whitelist' => array(
        'NmdaWebApi\\V1\\Rpc\\Hola\\Controller' => array(
            0 => 'application/vnd.nmda-web-api.v1+json',
            1 => 'application/json',
            2 => 'application/*+json',
        ),
'content_type_whitelist' => array(
        'NmdaWebApi\\V1\\Rpc\\Hola\\Controller' => array(
            0 => 'application/json',
        ),

This is how I have the controller

class HolaController extends AbstractActionController{
        public function holaAction(){
                return array(1,2,3,4,5);}}

And here is the returned json.

{"0":1,"1":2,"2":3,"3":4,"4":5}

I'm getting this list and a I want an array. Here is another example.

return array(1,2,3,4,array(5,6,7));
{"0":1,"1":2,"2":3,"3":4,"4":[5,6,7]}

Can someone explain me how to avoid this?

Edit_1

I figured out a workaround. Using HalJson fixes the problem. But i still cant understand why it doesnt work with normal Json.

'controllers' => array(
        'NmdaWebApi\\V1\\Rpc\\Hola\\Controller' => 'HalJson',

if it suits you try to return array('ids' => array(1,2,3,4,5)); than you will have your array but in key "ids" — tasmaniski
– tasmaniski, Commented Mar 2, 2015 at 22:14

itrascastro · Accepted Answer · 2015-03-03 11:21:31Z

2

In your action you must return a JsonModel. To do that, first create a 'strategies' key under your 'view_manager' section in your module.config.php:

'view_manager' => array(
    'strategies'                => array(
        'ViewJsonStrategy',
    ),
),

Now you can return a JsonModel in your action:

$data = array(1, 2, 3, 4, 5);

return new JsonModel([
    'data' => $data
]);

edited Mar 3, 2015 at 11:21

answered Mar 3, 2015 at 11:06

itrascastro

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2 Comments

Hristo Ivanov Over a year ago

I'm going to give it a try.

Hristo Ivanov Over a year ago

Returning JsonModel from my Controller class work. I just use it like this. return new JsonModel($data);.

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