Java Split a String with Regex expression

Question

I don't know much about regex. So can you please tell me how to split the below string to get the desired output?

String ruleString= "/Rule/Account/Attribute[N='accountCategory' and V>=1]"+
                " and /Rule/Account/Attribute[N='accountType' and V>=34]"+
                  " and /Rule/Account/Attribute[N='acctSegId' and V>=341]"+
                   " and /Rule/Account/Attribute[N='is1sa' and V>=1]"+
                    " and /Rule/Account/Attribute[N='isActivated' and V>=0]"+
                    " and /Rule/Account/Attribute[N='mogId' and V>=3]"+
                    " and /Rule/Account/Attribute[N='regulatoryId' and V>=4]"+
                    " and /Rule/Account/Attribute[N='vipCode' and V>=5]"+
                    " and /Rule/Subscriber/Attribute[N='agentId' and V='346']";

Desired output:

a[0] = /Rule/Account/Attribute[N='accountCategory' and V>=1]

a[1] = /Rule/Account/Attribute[N='accountType' and V>=34]
.
.
.

a[n] = /Rule/Subscriber/Attribute[N='agentId' and V='346']

We can not simply split a string using " and " as we have two of those in the string (one is required and other one is not)

I want to split it something like this

String[] splitArray= ruleString.split("] and ");

But this won't work, as it will remove the end bracket ] from each of the splits.

Avinash Raj · Accepted Answer · 2015-03-19 14:24:41Z

2

Split your input according to the below regex.

String[] splitArray= ruleString.split("\\s+and\\s+(?=/)");

This splits the input according to the and which exits just before to the forward slash.

answered Mar 19, 2015 at 14:24

Avinash Raj

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2 Comments

Bhuvan Over a year ago

Hi.. Can you add another regex in this answer to split the string according to this pattern? --> ] and /

Bhuvan Over a year ago

ok.. got it.. I think its this --> ruleString.split("(?<=\])\\s*and\\s*(?=/)");

Rohit Jain · Accepted Answer · 2015-03-19 14:25:10Z

2

You have to use look-behind here:

String[] splitArray= ruleString.split("(?<=\\])\\s*and\\s*");

answered Mar 19, 2015 at 14:25

Rohit Jain

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2 Comments

Bhuvan Over a year ago

Can you please explain whats happening in this regex? I don't know much about regex

Jean-François Corbett Over a year ago

Reference - What does this regex mean?

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