Split a string in java using regex

Question

I am trying to split a string using a regex "A.*B", which works just fine to retrieve strings between 'A' and 'B'. But the dot '.' doesn't include new line characters \n,\r. Can you please guide me on how to achieve this?

Thanks

Thanks all. Pattern.DOTALL worked like a charm.

I had another question related to this. What should be done if I need to extract all the strings between 'A' and 'B' (which basically match the above regex).

I tried using find() and group() of matcher class, but with the pattern below it seems to return the whole string.

Pattern p = Pattern.compile("A.*B",Pattern.DOTALL);

does A[.\n\r]*B work ?

A.B.Cade
– A.B.Cade

2012-03-14 11:27:51 +00:00
Commented Mar 14, 2012 at 11:27 — A.B.Cade
– A.B.Cade, Commented Mar 14, 2012 at 11:27

nd. · Accepted Answer · 2012-03-14 11:29:21Z

1

Use a java.util.regex.Pattern with the MULTILINE flag:

import java.util.regex.Pattern;

Pattern pattern = Pattern.compile("A.*B", Pattern.MULTILINE);
pattern.split(string);

answered Mar 14, 2012 at 11:29

nd.

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Comments

Michał Kosmulski · Accepted Answer · 2012-03-14 11:29:59Z

1

Compile the regex with this option: Pattern regex = Pattern.compile("A.*B",Pattern.DOTALL)

answered Mar 14, 2012 at 11:29

Michał Kosmulski

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Jakub Zaverka · Accepted Answer · 2012-03-14 11:35:00Z

1

Try "A[.\\s]*B"

Or you may specify the DOTALL switch so that "." will include even line terminators. Take a look ať the documentation of the Pattern class.

edited Mar 14, 2012 at 11:35

answered Mar 14, 2012 at 11:29

Jakub Zaverka

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Haderlump · Accepted Answer · 2012-03-14 11:29:57Z

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Have a look at java.util.regex.Pattern.compile(String regex, int flags), esp. the DOTALL flag

answered Mar 14, 2012 at 11:29

Haderlump

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Kristof Mols · Accepted Answer · 2012-03-14 11:29:01Z

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I assume you use the Pattern, Matcher classes for this.

Have you tried providing MULTILINE to your Pattern.compile() method?

Pattern.compile(regex, Pattern.MULTILINE)

'.' = Any character (may or may not match line terminators)

http://docs.oracle.com/javase/1.4.2/docs/api/java/util/regex/Pattern.html#lt

answered Mar 14, 2012 at 11:29

Kristof Mols

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Tomas Narros · Accepted Answer · 2012-03-14 11:29:47Z

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Try changing yor regex to "A(.|\\s)*B" This means A followed by any character(.) or any white character(\s) any number of times followed by B (double scaped \s is needed at java Code).

Reference for Regular Expressions (constructs, spacial characters, etc.) in Java: http://docs.oracle.com/javase/6/docs/api/java/util/regex/Pattern.html

answered Mar 14, 2012 at 11:29

Tomas Narros

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