PHP ternary operator not working but does not display any error

Question

<?php
    /*if(isset($_COOKIE["telcoProvider"])) {
        $telcoProvider = $_COOKIE["telcoProvider"];

    } else {
        $telcoProvider = "NOT FOUND";
    }*/

    $telcoProvider = isset($_COOKIE["telcoProvider"]) ? $_COOKIE["telcoProvider"] : "NOT FOUND".

    print "<p>Your telecommunication company is <b>$telcoProvider.</b></p>";
?>

I have checked the browser and the Cookie is there.

It works with the normal if-else, but not with the ternary operator. It does not proceed to the print, yet, it does not display any error either.

What am I missing?

You have a typo, you need to finish your statement with ;, not with a dot. — jeroen
– jeroen, Commented Apr 7, 2015 at 8:34

Hanky Panky · Accepted Answer · 2015-04-07 08:43:30Z

2

$telcoProvider = isset($_COOKIE["telcoProvider"]) ?
 $_COOKIE["telcoProvider"] : "NOT FOUND".
                                        ^

What's that dot (.) doing there instead of a ; ?

I wonder why Eclipse did not say anything?

Try this and you will get to an answer to that question :) Note the dot before print

$test= 1==1? "Oh nice no print :P " : "Oh" . print("Really?");
var_dump($test);

edited Apr 7, 2015 at 8:43

answered Apr 7, 2015 at 8:34

Hanky Panky

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1 Comment

Mark Baker Over a year ago

Eclipse didn't say anything because it's perfectly valid PHP, just not what you wanted

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