Java SAX parsing of an XML String

Question

I have a situation, where I get a string representation of an XML and I would like to parse it using SAX parser.

I know there is a way to use document builder in order to get a DOM document and parse it using DOM parser, but I would like to parse it using SAX.

I don't want to save it to a file and read it using the SAX parser, unless this is the only option.

What should I do in this situation?

Evgeniy Dorofeev · Accepted Answer · 2015-04-18 06:03:05Z

5

Use SAXParser.parse(InputSource is, DefaultHandler dh) where

 InputSource is = new InputSource(new StringReader(str));

answered Apr 18, 2015 at 6:03

Evgeniy Dorofeev

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4 Comments

theexplorer Over a year ago

how would a method that gets the string as an argument look like? what will parse return? can you please edit and write it as a method?

theexplorer Over a year ago

something like:

public static Document loadXML(String xml) throws Exception {    DocumentBuilderFactory fctr = DocumentBuilderFactory.newInstance();    DocumentBuilder bldr = fctr.newDocumentBuilder();    InputSource insrc = new InputSource(new StringReader(xml));    return bldr.parse(insrc); }

theexplorer Over a year ago

sorry but it didn't help.. I'm new to this so any chance you can elaborate?

Evgeniy Dorofeev Over a year ago

SAXParserFactory.newInstance().newSAXParser().parse(inputSource, defaultHandler); the processing of events happens in DefaultHandler, you need to write it yourself

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