Java XML parsing

Question

Whats the quickest way to convert a doc like:

<customermodel:Customer>
    <creditCards>
        <cardNumber>@0</cardNumber>
        <provider>@HSBC</provider>
        <xsi:type>@customermodel:CreditCard</xsi:type>
             23242552
    </creditCards>
    .
    .

So that the elements with @ become attributes for the parent element.

ie get to:

<customermodel:Customer>
    <creditCards cardNumber="0" provider="HSBC" xsi-type="customermodel:CreditCard>
         232323232
    </creditCards>
        .
        .

Using a dom? or Sax parser or manually? and i can move the @ into the <>'s

use vtd-xml, better than DOM, SAX or Pull.

vtd-xml-author
– vtd-xml-author

2011-03-20 03:10:00 +00:00
Commented Mar 20, 2011 at 3:10 — vtd-xml-author
– vtd-xml-author, Commented Mar 20, 2011 at 3:10

jelovirt · Accepted Answer · 2009-05-10 14:50:26Z

If you decide to use XSLT, it will look something like

  <!-- process element and attributes first so that whitespace doesn't interfere -->
  <xsl:template match="creditCards">
    <xsl:copy>
      <xsl:apply-templates select="* | @*"/>
      <xsl:apply-templates select="text()"/>
    </xsl:copy>    
  </xsl:template>

  <!-- change childrent of creditCards to attributes and strip first charcter from value -->
  <xsl:template match="creditCards/*">
    <xsl:attribute name="{name()}">
      <xsl:value-of select="substring(., 2)"/>
    </xsl:attribute>
  </xsl:template>

  <!-- rename xsi:type -->
  <xsl:template match="creditCards/xsi:type">
    <xsl:attribute name="xsi-type">
      <xsl:value-of select="substring(., 2)"/>
    </xsl:attribute>
  </xsl:template>

  <!-- identity transform -->
  <xsl:template match="node() | @*">
    <xsl:copy>
      <xsl:apply-templates select="node() | @*"/>
    </xsl:copy>
  </xsl:template>

paweloque · Accepted Answer · 2009-04-03 14:10:30Z

1

The best way to work directly with XML data is to use XQuery. It is not the easiest thing to learn, but if you work a lot with XML it is very useful.

Some IDE even support XQuery editing (like Oxygen XML).

http://de.wikipedia.org/wiki/XQuery http://www.oxygenxml.com/

answered Apr 3, 2009 at 14:10

paweloque

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Comments

chburd · Accepted Answer · 2009-04-03 14:14:54Z

1

I think XSLT is the way to go.

More details here

And use a SAX parser, unless you have very good reasons.

answered Apr 3, 2009 at 14:14

chburd

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Mutant · Accepted Answer · 2009-04-03 14:10:31Z

0

Below link might be helpful

http://www.totheriver.com/learn/xml/xmltutorial.html#5

answered Apr 3, 2009 at 14:10

Mutant

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