Every row of my list goes like this:
[(21, ['Rodriguez', 'Lara', 'Vicky', '55302292'])]
and I want it to print just the name, in this case Vicky. The code I use is this
for x in numbers:
r=str(x)
d1= r.split(',')
print ('D1', d1)
and it prints this:
['[(21', " ['Rodriguez'", " 'Lara'", " 'Vicky'", " '55302292'])]"]
Don't turn your perfectly good list into a string! just use indexing:
x[0][1][2]
To illustrate what this does:
>>> x = [(21, ['Rodriguez', 'Lara', 'Vicky', '55302292'])]
>>> x[0]
(21, ['Rodriguez', 'Lara', 'Vicky', '55302292'])
>>> x[0][1]
['Rodriguez', 'Lara', 'Vicky', '55302292']
>>> x[0][1][2]
'Vicky'
Each additional subscription ([...]) drills deeper into the nested structure; x[0] extracts the tuple from the list; x[0][1] then accesses the list value in that tuple (x[0][0] would give you 21), and x[0][1][2] give you back 'Vicky', the third element in that nested list.
Get the list first, then extract data from it
>>> list = [(21, ['Rodriguez', 'Lara', 'Vicky', '55302292'])]
>>> names = list[0][1]
>>> names
['Rodriguez', 'Lara', 'Vicky', '55302292']
>>> names[2]
Vicky
Try this:
for x in numbers:
r=str(x)
a=r.split(',')
print (a[3].strip("' "))
You can iterate over your list, while unpacking a tuple in each iteration. This would make it slightly more clean/readable.
>>> x = [(21, ['Rodriguez', 'Lara', 'Vicky', '55302292']), (22, ['Micheal', 'Jackson', 'John', '66302292'])]
>>> for age, details in x:
... print details[2]
...
Vicky
John
[(21, ['Rodriguez', 'Lara', 'Vicky', '55302292'])][0][1][2]:)