Store multiple inputs in multiple variables in bash

Question

I need to make a loop about this script:

#!/bin/bash
exec 3>&1;
result=$(dialog --inputbox "Scan S/N" 10 23 2>&1 1>&3);
result1=$(dialog --inputbox "Scan S/N" 10 23 2>&1 1>&3);
result2=$(dialog --inputbox "Scan S/N" 10 23 2>&1 1>&3);
exec 3>$-;
clear
echo $result;
echo $result1;
echo $result2;

And would be great to have a varible where i can select how many times will the loop run...

I dont have to tell you im pretty newbie in this hehe, thanks in advance. JB

based on your minimal description of the use-case, you don't need to worry about exec n>&n code. Leave them out, it will just confuse things. Good luck. — shellter
– shellter, Commented Sep 22, 2016 at 19:37

chepner · Accepted Answer · 2016-09-22 19:53:14Z

1

Anytime you talk about a variable number of related variables, you want an array.

n=3
for ((i=0; i<n; i++)); do
    results+=( $(dialog --inputbox "Scan S/N" 10 23 2>&1)) 
done

# individual results can be accessed with ${results[i]} for i=0,1,...,n-1
for res in "${results[@]}"; do
  echo "$res"
done

answered Sep 22, 2016 at 19:53

chepner

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Comments

Gilles Quénot · Accepted Answer · 2016-09-22 18:23:58Z

0

The basic way to loop and count is :

c=0
while true; do
  echo "count $c"
  ((c++))
  ((c==100)) && break
done

echo DONE

answered Sep 22, 2016 at 18:23

Gilles Quénot

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