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I currently have a list of URLs

http://www.website.com/dynamic/download.ashx?id=123/12/12345
http://www.website.com/dynamic/download.ashx?id=12/121/123451
http://www.website.com/dynamic/download.ashx?id=1/1233/123

I am looking to create a new list replacing the / with _ and stripping the URL. Creating a new list:

123_12_12345
12_121_123451
1_1233_123

I have removed the URL by splitting

for z in columns['location']:
    print z.split('=')[1:]enter code here
    stripped.append(z.split('=')[1:])

help to replace / with _ would be appreciated. cheers!

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2 Answers 2

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This will split about =, grab the second part and then replace / with _.

urls = ["http://www.website.com/dynamic/download.ashx?id=123/12/12345",
        "http://www.website.com/dynamic/download.ashx?id=12/121/123451",
        "http://www.website.com/dynamic/download.ashx?id=1/1233/123"]

for url in urls:
    print(url.split("=")[1].replace("/","_"))
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0
newink = a.split('=')[0] + a.split('=')[1].replace('/','_')

Then loop for each link to convert it

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