Regex Extraction in Scala

Question

I have a text file that has some data like this :-

1/4 cup chopped green onion
1/2 teaspoon salt
1 Tbsp cream
1 teaspoon vanilla extract

I want to write a regexp such that my data is divided into groups of 3 like below:-

'1/4' 'çup' 'chopped green onion'
'1/2' 'teaspoon' salt'
'1' 'Tbsp' 'cream'
'1' 'teaspoon' 'vanilla extract'

It means that my regex should have:

the first group before the first space,
second group between the first and second space and
third group after the second space till the end of line.

What is a possible way to do that?

I know you are asking for Scala, and a regex. You could achieve by using split method and split each line by space. It will be converted to array, and then from that string array you could have 1/4 and cup in the 0th and 1th position. Rest strings you can again merge to form a string. just suggesting a workaround. — inquisitive
– inquisitive, Commented Jun 18, 2015 at 6:29
Show the regex you tried and why it didn't work. If you didn't attempt it yet, check the regex documentation. — Alexis C.
– Alexis C., Commented Jun 18, 2015 at 6:30
to get started here is sample regex that will match line breaks regex101.com/r/pF9cV2/1. — Kamran
– Kamran, Commented Jun 18, 2015 at 6:32

AmigoNico · Accepted Answer · 2015-06-18 06:53:33Z

2

scala> val RecipeItem = """(\S+)\s+(\S+)\s+(.*)""".r
RecipeItem: scala.util.matching.Regex = (\S+)\s+(\S+)\s+(.*)

scala> val RecipeItem(qty, unit, ingredient) = "1/4 cup chopped green onion"
qty: String = 1/4
unit: String = cup
ingredient: String = chopped green onion

answered Jun 18, 2015 at 6:53

AmigoNico

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