scala regex : extract from string

Question

I am trying to extract few values out of an big string , I have an hard time extracting them , I have tired a couple of regex patterns , but they always give me no match. Anyway they seem to work in the online regex sites available but not in Scala. What I am trying to do is

Input :

ESSSTOR\Disk&Ven_VendorName&Prod_MO_Might_MS_5.0&Rev_6.01\08765J54U3K4QVR0&0

Extract [output]:

Vendorname

MO_Might_MS_5.0&Rev_6.01

08765J54U3K4QVR0&0

I am trying to extract those three values from the input string , but unable to do so.

Can some one please me see what I am doing wrong.

Thanks in advance.

//Input value

  val device:String=  "ESSSTOR\\Disk&Ven_VendorName&Prod_MO_Might_MS_5.0&Rev_6.01\\08765J54U3K4QVR0&0"

// Regex build for product extraction

           val proReg=  """.*[Prod_]([^\\\\]*)""".r
                     // """.*Prod_([^\\\\]*)""".r  -- no match as output
                    // """(?:Prod_)([^\\\\]*)""".r  -- no match as output

      println("Device: "+device)

    // method -1:   
    device match{

      case proReg(prVal) => println(s"$prVal is product val")
      case _ =>  println("no match")   }

    // method-2 : 

   val proReg(g1) = "ESSSTOR\\Disk&Ven_VendorName&Prod_MO_Might_MS_5.0&Rev_6.01\\08765J54U3K4QVR0&0"
   println(s"group1: $g1 ")


   O/P:


  Device:  ESSSTOR\Disk&Ven_VendorName&Prod_MO_Might_MS_5.0&Rev_6.01\08765J54U3K4QVR0&0

   //method-1

   no match

   // method-2

   error

// Regex build for dev serial

    val serReg = """(?:Prod_\\S*[\\\\])(.*)""".r

    device match {
      case serReg(srVal) => println(s"$srVal is product val")
      case _ => println("no match")
    }


    o/p:

    no match

// Regex for vendor

    val venReg="""(?:Ven_)([^&]*)""".r

    device match {
      case venReg(vnVal) => println(s"$vnVal is vendor val")
      case _ => println("no match")
    }


    o/p:

    no match

@jwvh : please help me see what I am doing wrong

codehunter
– codehunter

2017-09-14 16:43:18 +00:00
Commented Sep 14, 2017 at 16:43 — codehunter
– codehunter, Commented Sep 14, 2017 at 16:43

jwvh · Accepted Answer · 2017-09-14 17:55:33Z

2

See if this gets closer to what you want.

val pttrn = raw"Ven_([^&]+)&Prod_([^&]+)&Rev_6.01\\(.*)".r.unanchored

device match {
  case pttrn(ven, prod, rev) => 
      s"vendor: $ven\nproduct: $prod\nrevNum: $rev"
  case _ => "does not match pattern"
}

explanation

Ven_([^&]+) --> Look for something that begins with Ven_. Capture everything that isn't an ampersand &.

&Prod_([^&]+) --> That should be followed by the Prod_ string. Capture everything that isn't an ampersand &.

&Rev_6.01\\(.*) --> That should be followed by the Rev_ string that ends with a single backslash \. Capture everything that follows.

edited Sep 14, 2017 at 17:55

answered Sep 14, 2017 at 17:05

jwvh

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4 Comments

codehunter Over a year ago

it throws an Exception in thread "main" scala.MatchError: and there is no explanation to it.

jwvh Over a year ago

@codehunter; It passes my tests. Check that the device string contains a single backslash \ separating Rev_6.01 from the target string.

codehunter Over a year ago

It worked !! :) What ever you wrote is simple , I dont why I got myself into using non capturing groups and nothing worked. I did upvote and marked the answer as correct , as I have less points it is not shown in public.

som-snytt Over a year ago

We sure need better tooling for regexes besides SO and jwh and besides those worksheet sites.

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