django: ModelForm access instance of new object

Question

I wanted to ask if there is a way to access instance id in ModelForm save method. (Need an object in order to add some extra data).

def save(self, *args, **kwargs):
    instance = super(MyForm, self).save(*args, **kwargs)
    print instance 
    return instance

And in all cases I am getting instance before it's saved in database (so it does not have an id and I can't attach objects to it)

It's a bit strange. When I do print kwargs it says {'commit': False}. interesting why — Oleg Tarasenko
– Oleg Tarasenko, Commented Jun 22, 2015 at 16:48

allanlasser · Accepted Answer · 2015-06-22 16:31:36Z

1

It isn't necessary to override the ModelForm save() function. Instead, it's better to call save with commit=False. The Django docs explain this in depth, but here's a quick example:

new_object = form.save(commit=False)
new_object.name = 'Whatever'
new_object.save()

By calling save with commit=False, you get an object back. You can do whatever you want with this object, but make sure to save it once you make your changes!

answered Jun 22, 2015 at 16:31

allanlasser

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2 Comments

Oleg Tarasenko Over a year ago

Well the thing is that I am not processing this form in my view. It's more like xadmin form, I have added for a specific model. So in general I can only tweak all form methods.. but can't access views

allanlasser Over a year ago

Hm, well in that case sorry my answer wasn't helpful. Does the admin library you're using offer for class overrides and registrations, as the Django admin does?

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