I have an array like this
records =
[
["a","1"],
["b","2"],
["c","3"]
]
I want to pull the number 3, given that I known I am searching for the value of "c".
I've tried this but no luck
search_for = 'c'
test = records.select{ |x| x=search_for}
I get back the whole array
You're looking for Array#assoc:
records.assoc(search_for).last
.last. I suggest your write records.assoc('c').last => "3". I'll delete this comment when you've seen it (no reply req'd). Also, the link for the method is ruby-doc.org/core-2.2.0/Array.html#method-i-assoc .
You can convert you array to hash and just get the value like this:
search_for = 'c'
test = Hash[records][search_for] #=> "3"
You may also consider to use .key? to check if key is present.
.key?
Hash.key?(k) is the same as Hash.has_key?(k) and Hash.include?(k).Not necessarily the cleanest or most idiomatic, but here's another way:
records.find { |x, y| break(y) if x == "c" }
In other words, given an array of pairs x, y, find the first pair where x == "c" and return the value of y.
.last like in seph's* answertest = records.select{ |x| x[0] == search_for }
value = test[0][1]
records.find { |f,_| f == 'c' }.last #=> 3
You can use Array#include?(value):
Example:
a = [1,2,3,4,5]
a.include?(3) # => true
a.include?(9) # => false
