Flattening multidimensional arrays in javascript

Question

I need to flatten multidimensional arrays but my code only flattens one array and then stops. What is wrong? How do I get it to only transfer the elements with no arrays.

 function flatten(arr) {
     // I'm a steamroller, baby
     arr.reduce(function (flat, toFlatten) {
        return flat.concat(Array.isArray(toFlatten) ? flatten(toFlatten) : toFlatten);
     },[]);
    }
    flatten([[['a']], [['b']]]); 

assert.deepEqual(flatten([[['a']], [['b']]]), ['a', 'b'], 'should flatten nested arrays');

should flatten nested arrays: expected [ [ 'a' ], [ 'b' ] ] to deeply equal [ 'a', 'b' ]

possible duplicate of Merge/flatten an Array of Arrays in JavaScript? — Nick Grealy
– Nick Grealy, Commented Jul 1, 2015 at 23:08

Rob Lyndon · Accepted Answer · 2015-07-01 21:21:12Z

1

You're doing it right -- just missing a return statement.

function flatten(arr) {
    // I'm a steamroller, baby
    return arr.reduce(function (flat, toFlatten) {
        return flat.concat(Array.isArray(toFlatten) ? flatten(toFlatten) : toFlatten);
    }, []);
}

console.log(flatten([[['a']], [['b']]]));

answered Jul 1, 2015 at 21:21

Rob Lyndon

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Comments

YousefHany · Accepted Answer · 2022-03-01 22:03:28Z

0

let myarray = [
    1000,
    [1, 2, 3, 4],
    [5, 6, 7],
    [999, [10, 20, [100, 200, 300, 400], 40], [50, 60, 70]],
  ];
  
function f(array) {
  let result = [];
  function flatten(array) {
    for (let i = 0; i < array.length; i++) {
      if (!Array.isArray(array[i])) {
        result.push(array[i]);
      } else {
        flatten(array[i]);
      }
    }
    return result;
  }
  return flatten(array);
}

answered Mar 1, 2022 at 22:03

YousefHany

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