JSON.parse from php's json_encode issue

Question

Running an issue with parsing JSON recieved from php backend. On php i have an array, which i send by json_encode:

$result[] = (object) array('src' => "{$mergedFile}", 'thumb_src' => "{$thumb_file}");
echo json_encode($result);

And when trying to JSON.parse it i recieve error:

"Uncaught SyntaxError: Unexpected token F"

The response itself looks this like:

[{"src":"upload\/lessons\/963\/video\/176481500-m.webm","thumb_src":"upload\/lessons\/963\/slide\/thumb_0f515a62753626e1aaefdc7968e8103e.jpg"}]

Very strange thing is that, similar code works nearby.. looks fine.. Appreciate any help, thanks.

You JSON is fine, the PHP code you have on the backed probably isnt. — Daan
– Daan, Commented Jul 2, 2015 at 7:01
nothing special there, i just do JSON.parse(data) ... the data i recieve in request's callback — Lazyexpert
– Lazyexpert, Commented Jul 2, 2015 at 7:20
I've solved this using regexps, but i still would like to hear the correct answer, thx. — Lazyexpert
– Lazyexpert, Commented Jul 2, 2015 at 7:33

davidkonrad · Accepted Answer · 2015-07-02 07:04:54Z

2

You cannot JSON.parse() JSON, the param must be a string :

JSON.parse('[{"src":"upload\/lessons\/963\/video\/176481500-m.webm","thumb_src":"upload\/lessons\/963\/slide\/thumb_0f515a62753626e1aaefdc7968e8103e.jpg"}]');

the error you receive can easily be reproduced by :

JSON.parse([{"src":"upload\/lessons\/963\/video\/176481500-m.webm","thumb_src":"upload\/lessons\/963\/slide\/thumb_0f515a62753626e1aaefdc7968e8103e.jpg"}]);

answered Jul 2, 2015 at 7:04

davidkonrad

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1 Comment

Lazyexpert Over a year ago

You're right, but strange. Look, i receive data in callback of request. Typeof(data) == string, data is the same as response, but i cannot do parse, why?

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