Regular Expression in Python using re.split and pattern

Question

I have a string like this:

string ='ArcelorMittal invests =E2=82=AC87m in new process that cuts emissions=20'

I want to take out =E2=82=AC and =20

But when I use,

pattern ='(=\w\w)+'
a=re.split(pattern,string)

it returns

['ArcelorMittal invests ', '=AC', '87m in new process that cuts emissions', '=20', '']

Avinash Raj · Accepted Answer · 2015-07-14 07:45:05Z

1

You may use re.findall

>>> s = 'ArcelorMittal invests =E2=82=AC87m in new process that cuts emissions=20'
>>> re.findall(r'(?:=\w{2})+', s)
['=E2=82=AC', '=20']
>>>

Use re.sub if you want to remove those chars.

>>> re.sub(r'(?:=\w{2})+', '', s)
'ArcelorMittal invests 87m in new process that cuts emissions'

edited Jul 14, 2015 at 7:45

answered Jul 14, 2015 at 7:39

Avinash Raj

175k32 gold badges247 silver badges289 bronze badges

Sign up to request clarification or add additional context in comments.

4 Comments

Hung Dinh Nguyen Over a year ago

Thanks a lot for help, but I need to decode it then put them back later so I want to use an order array so I can join them after decode

Avinash Raj Over a year ago

I think you need to use re.sub

Hung Dinh Nguyen Over a year ago

thanks a lot avinash, I was extracting this text from gmail and they have some encoding problem , so I was gonna convert =E2=82=AC to /xE2/x82/xAC, then encode it to utf-8, then put back to the original string. Is there any way to work on it? thanks a lot

Avinash Raj Over a year ago

just replace = with /x . And also you may use re.split with your original but you have to turn capturing group to non-capturing group pattern =r'(?:=\w\w)+', so that it won't capture the delimiters.

Community · Accepted Answer · 2017-05-23 12:15:54Z

1

Based on your comment I would recommend you to use quopri.decodestring on original string. There is no need to extract these characters and decode them separately

>>> import quopri
>>> s = 'ArcelorMittal invests =E2=82=AC87m in new process that cuts emissions=20'
>>> quopri.decodestring(s)
'ArcelorMittal invests \xe2\x82\xac87m in new process that cuts emissions '
>>> print quopri.decodestring(s)
ArcelorMittal invests €87m in new process that cuts emissions

edited May 23, 2017 at 12:15

CommunityBot

11 silver badge

answered Jul 14, 2015 at 7:59

Konstantin

25.5k5 gold badges53 silver badges65 bronze badges

Collectives™ on Stack Overflow

Regular Expression in Python using re.split and pattern

2 Answers 2

4 Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

4 Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related